Question

我想使用js对对象数组进行排序。这是我实施的内容。

var employees = []
employees[0] = {
    retiredate: "01/12/2014"
}
employees[1] = {
    retiredate: "29/01/2015"
}
employees[2] = {
    retiredate: "05/12/2014"
}
employees[3] = {
    retiredate: "08/12/2014"
}
employees[4] = {
    retiredate: "11/12/2014"
}
employees[5] = {
    retiredate: "14/01/2015"
}
employees[6] = {
    retiredate: "03/12/2014"
}
employees[7] = {
    retiredate: "16/01/2015"
}
employees[8] = {
    retiredate: "19/01/2015"
}
employees[9] = {
    retiredate: "22/01/2015"
}
employees[10] = {
    retiredate: "28/01/2015"
}
employees[11] = {
    retiredate: "23/01/2015"
}
employees[12] = {
        retiredate: "15/01/2015"
    }
    //console.log(periodesSorted);

console.log("START  ... ")
employees.sort(function(a, b) {
    var dateA = new Date(a.retiredate),
        dateB = new Date(b.retiredate)
    return dateA - dateB //sort by date ascending
})

for (ind2 = 0; ind2 < employees.length; ind2++) {
    console.log(employees[ind2].retiredate)
}
console.log("End  ... ")

在firefox中，retiredate数组排序很好。

在chrome中，我有以下结果

结果未排序。我在哪里出错了？有人可以建议修复此问题吗？

此致

Answer 1

而不是：

new Date(a.retiredate)

在创建日期之前，将dd / mm / yyyy转换为yyyy-mm-dd：

new Date(a.retiredate.replace( /(\d{2})\/(\d{2})\/(\d{4})/, "$3-$2-$1") );

工作JSFiddle： http://jsfiddle.net/inanda/csz56b0q/1/

Answer 2

在我们的情况下，您需要将日期转换为mm/dd/yyyy格式，您可以这样做

employees.sort(function(a, b) {
  var toDate = function (date) {
    var res = date.split('/');
    return new Date(res[2], res[1], res[0]).getTime();

    // getTime returns the number of milliseconds
    // or you can use + before new Date..
  };

  return toDate(a.retiredate) - toDate(b.retiredate);
})

Example

Answer 3

您可以使用

employees.sort(function (d1, d2) {
  function parseDate(str) {
    var parts = str.match(/(\d+)/g);
    // assumes M/D/Y date format
    return new Date(parts[2], parts[0]-1, parts[1]); // months are 0-based
  }
  return parseDate(d1.retiredate) - parseDate(d2.retiredate);
});

这是示例Link

Answer 4

就我个人而言，我会避免所有重新解析＆amp;日期构建（样本中84次）;

// prepare the data by appending a date from a reformatted string
for (var i = 0; i < employees.length; i++) {
    var dateString = employees[i].retiredate;
    employees[i]._date = new Date(dateString.substr(6, 4) + "-" + dateString.substr(3, 2) + "-" + dateString.substr(0, 2));
}

// sort without conversion
employees.sort(function(a, b) {
    return a._date - b._date;
})

在数组中排序日期字符串

4 个答案: