Question

我按下按钮时试图在jtable列中隐藏和显示密码，我按下按钮时隐藏了密码，但当再次按下时，列变为空这是我的代码：

private String mask(int length) {
    StringBuilder sb = new StringBuilder(length);
    for (int i = 0; i < length; i++) {
        sb.append('\u25CF');
    }
    return new String(sb);
}
private String unmask(int length){
    StringBuilder sb = new StringBuilder(length);
    for (int i = 0; i < length; i++) {
        sb.append('\0');
    }
    return new String(sb);
}

masked=new DefaultTableCellRenderer(){
        private static final long serialVersionUID = 1L;
        public Component getTableCellRendererComponent(JTable arg0, Object arg1, boolean arg2, boolean arg3, int arg4, int arg5) {
            int length =0;
            if (arg1 instanceof String) {
                length =  ((String) arg1).length();
            } else if (arg1 instanceof char[]) {
                length = ((char[])arg1).length;
            }
            setText(mask(length));
            return this;
        }
    };

unmasked=new DefaultTableCellRenderer(){
                    private static final long serialVersionUID = 1L;
                    public Component getTableCellRendererComponent(JTable arg0, Object  arg1, boolean arg2, boolean arg3, int arg4, int arg5) {
                        int length =0;
                        if (arg1 instanceof String) {
                            length =  ((String) arg1).length();
                        } else if (arg1 instanceof char[]) {
                            length = ((char[])arg1).length;
                        }
                        setText(unmask(length));
                        return this;
                    }
                };

现在按钮代码：

//i have a global variable set to false,to detect if password is show
boolean show=false;
JButton showpass=new JButton("Show password");
showpass.addActionListener(new ActionListener(){
      public void actionPerformed(ActionEvent e){
             if(show==false){
                show=true;
                data.getColumnModel().getColumn(3).setCellRenderer(unmasked);//data it's the jtable
                tmodel.fireTableDataChanged();//tmodel it's the jtable model
             }else if(show==true){
                show=false;
                data.getColumnModel().getColumn(3).setCellRenderer(masked);
                tmodel.fireTableDataChanged();

             }          
      }
});

这是我在这里发表的第一篇文章，对不起英文不好

Answer 1

揭露中的

setText(unmask(length));是徒劳的。您无法仅从lenth恢复密码。

使用setText(arg1.toString());

在按下按钮的jtable列中显示和隐藏密码字符

1 个答案: