Question

您好我想打开一个txt文件（需要弹出打开文件对话框和当前模板相同的文件夹）

然后这个文件需要读作xlsx而不是txt。

这是我目前的代码设置：

Private Sub CommandButton1_Click()

Dim intChoice As Integer

'Select the start folder
Application.FileDialog(msoFileDialogOpen _
    ).InitialFileName = "I:\Group -*******Chages here******"
'make the file dialog visible to the user
intChoice = Application.FileDialog(msoFileDialogOpen).Show
'determine what choice the user made
If intChoice <> 0 Then

***** CODE HERE********

End If
End Sub

有人可以识别我的错误吗？

Answer 1

您可以尝试以下代码段（它可以）并根据您的开发任务进行修改：

Private Sub CommandButton1_Click()

   Dim fDialog As Office.FileDialog

   ' set up the File Dialog var
   Set fDialog = Application.FileDialog(msoFileDialogFilePicker)

   With fDialog

      'sample init file name
      .InitialFileName = "C:\Text.txt"

       ' set the title of the Dialog box
      .Title = "Please select the file to open"

      ' Clear the current and add some sample filters
      .Filters.Clear
      .Filters.Add "Text Files", "*.txt"
      .Filters.Add "Excel Files", "*.xls"
      .Filters.Add "All Files", "*.*"

      'Show dialog box: if .Show method returns True then execute the code
      If .Show = True Then
          'Add code here
      Else
         MsgBox "File Open operation Canceled."
      End If
   End With
End Sub

希望这可能会有所帮助。亲切的问候，

Answer 2

或者你可以使用它：

Dim fname
fname = Application.GetOpenFilename("Text Files (*.txt),*.txt", , , , True)
If IsArray(fname) Then Workbooks.OpenText fname(1)

要查看可用参数 OpenText Method 商品，请参阅MSDN。 HTH。

在Excel VBA中打开txt文件

2 个答案: