Question

所以我试图在函数内部运行一个预处理语句，但似乎很难通过mysqli连接语句。我现在肯定超过了100次尝试组合......

在函数中使用之前，我将连接用于另一个预准备语句。由于难以将include（）传递给函数

，我甚至在语句中声明了我的连接变量

include('phpsqlinfo_dbinfo.php');
$mysqli = new mysqli($host, $dbusername, $dbpassword, $database);

$stmt = $mysqli->prepare("SELECT id, email, username, password, gender, homelat")

//blah blah blah run a statement here. I omitted this statement for brevity purposes.

$stmt->close();
$mysqli->close();


function storeTokenForUser($username,$token) {
    echo "running2";

    echo $token;
    echo $username;
    $host="";
    $dbusername="XXXX";
    $dbpassword="XXXX";
    $database="XXXX";

    global $mysqli;

    $stmt=$mysqli->prepare("INSERT INTO cookielogin (username, token) VALUES (?,?)"); 
    $stmt->bind_param('ss', $username, $token1);
    $stmt->execute();
    if (mysqli_connect_errno()) {
            echo("error".htmlspecialchars($mysqli->error).htmlspecialchars($stmt1->error));
    }
    echo"running3";
}


function cookie($username,$mysqli) {
$token = md5(uniqid(mt_rand(), true));
storeTokenForUser($username, $token);
$cookie = $username . ':' . $token;
$mac = hash_hmac('sha256', $cookie, 9842);
$cookie .= ':' . $mac;
setcookie('rememberme', $cookie);
        echo"running1";
}

在我的努力中，我遇到了不同的错误，但是现在，这给了我：

Warning: mysqli::prepare(): Couldn't fetch mysqli in /var/www/loginphp.php on line 63

Fatal error: Call to a member function bind_param() on a non-object in /var/www/loginphp.php on line 64

真诚地感谢您的帮助。非常感谢。

Answer 1

卸下：

$stmt->close();
$mysqli->close();

修复错误并：

$stmt->bind_param('ss', $username, $token1);

$token1未定义。

mysqli在函数内部编写语句

1 个答案: