Question

我是python的初学者，我正在终端创建一个双人tic tac toe游戏。基本上，这个游戏有它的所有错误和纠结，但是，我有一个最后的问题。基本上，当提示输入移动时，如果一个用户在提示移动到某处时输入一个字母，如果输入了一个字母或非整数，它就会崩溃。这是代码，然后我会在游戏运行时输出输出，并且用户在提示移动后输入一个字母。

X = "X"
O = "O"
empty = " " 
S = [" ", " ", " ", " ", " ", " ", " ", " ", " "]

def Instructions():
    print "Fill in spaces on the board with number corresponding to the board below."
    print ""
    print "",1,"|",2,"|",3
    print "","---------"
    print "",4,"|",5,"|",6
    print "","---------"
    print "",7,"|",8,"|",9
    print ""

def Board():
    print ""
    print "",S[0],"|",S[1],"|",S[2]
    print "","---------"
    print "",S[3],"|",S[4],"|",S[5]
    print "","---------"
    print "",S[6],"|",S[7],"|",S[8], "\n"

def WhoGoesFirst():
    Instructions()
    global order
    letter = raw_input('Who goes first, X or O? ').upper()
    while not (letter == "X" or letter == "O"):
        letter = raw_input('Who goes first, X or O? ').upper()
    if letter == "X":
        order = [X, O, X, O, X, O, X, O, X]
    else:
        order = [O, X, O, X, O, X, O, X, O]

def CheckWin():
    global winner
    winner = ""
    if S[0] == S[1] == S[2] != empty:
        winner = S[0]
    if S[3] == S[4] == S[5] != empty:
        winner = S[3]
    if S[6] == S[7] == S[8] != empty:
        winner = S[6]
    if S[0] == S[3] == S[6] != empty:
        winner = S[0]
    if S[1] == S[4] == S[7] != empty:
        winner = S[1]
    if S[2] == S[5] == S[8] != empty:
        winner = S[2]
    if S[0] == S[4] == S[8] != empty:
        winner = S[0]
    if S[2] == S[4] == S[6] != empty:
        winner = S[2]

def Move(turn):
    move = input('Choose a Space from 1-9 for ' + str(order[turn]) + ' to Go: ')
    while move not in range (1, 10) or S[int(move) - 1] is not empty:
        move = input('Choose a Space from 1-9 for ' + str(order[turn]) + ' to Go: ')
    S[int(move) - 1] = order[turn]
    Board()
    CheckWin()

def MakeMove():
    turn = 0
    while turn <= 8:
        Move(turn)
        turn += 1
        if winner == X or winner == O:
            while turn <= 8:
                turn += 1
            if winner == X:
                print winner + " Is the Winner!"
            if winner == O:
                print winner + " Is the Winner!"
    if winner == "":
        print "The Game Is a Tie"

WhoGoesFirst()
MakeMove()

输出

Fill in spaces on the board with number corresponding to the board below.

 1 | 2 | 3
 ---------
 4 | 5 | 6
 ---------
 7 | 8 | 9

Who goes first, X or O? x
Choose a Space from 1-9 for X to Go: 1

 X |   |  
 ---------
   |   |  
 ---------
   |   |   

Choose a Space from 1-9 for O to Go: k
Traceback (most recent call last):
  File "move.py", line 79, in <module>
    MakeMove()
  File "move.py", line 66, in MakeMove
    Move(turn)
  File "move.py", line 56, in Move
    move = input('Choose a Space from 1-9 for ' + str(order[turn]) + ' to Go: ')
  File "<string>", line 1, in <module>
NameError: name 'k' is not defined

是否有可能解决这个问题，因此如果输入了一个not-intiger，它将再次提示移动，（直到放入适当的移动）。如果有可能，那么它将如何完成。

Answer 1

是的，要解决立即问题，请使用raw_input。

在Python 2下，input会从您那里获得一个值，然后尝试对其进行评估。评估1是可以的，但在没有这样的情况下评估k变量不是。

一旦你有了字符串，你可以在尝试将它转换为整数之前检查它，例如：

def Move(turn):
    move = -1
    while move not in range (1, 10) or S[int(move) - 1] is not empty:
        smove = raw_input('Choose a Space from 1-9 for ' + str(order[turn]) + ' to Go: ')
        try: 
            move = int(smove)
        except ValueError:
            move = -1
    S[int(move) - 1] = order[turn]
    Board()
    CheckWin()

Python 3也是一个修复，因为它的input函数等同于Pyhon 2的raw_input。

Answer 2

调用input时，值必须在语法上正确python。

此功能不会捕获用户错误。如果输入语法无效，则会引发SyntaxError。如果评估过程中出现错误，可能会引发其他异常

另一方面，raw_input被认为是一个字符串。

然后函数从输入中读取一行，将其转换为字符串（剥离尾随换行符），然后返回该行。

Python tic tac toe输入错误

2 个答案: