计算在.Net中以X行显示文本所需的最小宽度？

Question

如果文本在空白处打破，你如何计算在X行中显示字符串所需的最小宽度？

Answer 1

可能的提示：也许某种使用Graphics.MeasureString（）的二进制搜索？

Answer 2

编辑：没有意识到您想尝试将文本调整为固定数量的行。这是一个艰难的尝试和解决。这是我能想到的最好的，可能不是最优雅的，但似乎有效：

public SizeF CalculateWidth(Font font, Graphics graphics, int numOfLines,
                            string text)
{
    SizeF sizeFull = graphics.MeasureString(text, font,
                                            new SizeF(
                                                float.PositiveInfinity,
                                                float.PositiveInfinity),
                                            StringFormat.
                                                GenericTypographic);

    float width = sizeFull.Width/numOfLines;
    float averageWidth = sizeFull.Width/text.Length;
    int charsFitted;
    int linesFilled;

    SizeF needed = graphics.MeasureString(text, font,
                                          new SizeF(width,
                                                    float.
                                                        PositiveInfinity),
                                          StringFormat.
                                              GenericTypographic,
                                          out charsFitted,
                                          out linesFilled);

    while (linesFilled > numOfLines)
    {
        width += averageWidth;
        needed = graphics.MeasureString(text, font,
                                        new SizeF(width,
                                                  float.PositiveInfinity),
                                        StringFormat.GenericTypographic,
                                        out charsFitted, out linesFilled);
    }

    return needed;
}

使用示例：

Font font = new Font("Arial", 12, FontStyle.Regular,
                     GraphicsUnit.Pixel);
Graphics g = Graphics.FromImage(new Bitmap(1, 1));
string text = "Some random text with words in it.";

SizeF size = CalculateWidth(font, g, 3, text);