我有一个名为trades
的表,用于使用以下架构持有货币交易数据:
id - uuid
timestamp - timestamp without time zone
price - numeric
我希望能够以一种可以构建蜡烛图的方式进行查询。为此,我需要第一个价格,最后价格,最高价格和最低价格,按分组时间间隔。到目前为止,我有这个:
CREATE FUNCTION ts_round( timestamptz, INT4 ) RETURNS TIMESTAMPTZ AS $$
SELECT 'epoch'::timestamptz
+ '1 second'::INTERVAL * ( $2 * ( extract( epoch FROM $1 )::INT4 / $2 ) );
$$ LANGUAGE SQL;
SELECT ts_round( timestamp, 300 ) AS interval_timestamp
, max(price) AS max, min(price) AS min
FROM trades
GROUP BY interval_timestamp
ORDER BY interval_timestamp DESC
如何在这些时间间隔内获得第一个价格和最后价格?
答案 0 :(得分:4)
我认为这是您想要的查询:
SELECT ts_round( timestamp, 300 ) AS interval_timestamp,
max(firstprice) as firstprice,
max(lastprice) as lastprice,
max(price) AS maxprice, min(price) AS minprice
FROM (SELECT t.*,
first_value(price) over (partition by ts_round(timestamp, 300) order by timestamp) as firstprice,
first_value(price) over (partition by ts_round(timestamp, 300) order by timestamp desc) as lastprice
FROM trades t
) t
GROUP BY interval_timestamp
ORDER BY interval_timestamp DESC;
答案 1 :(得分:2)
这对所有窗口函数使用单个窗口,没有子查询。应该比目前接受的答案更快。
SELECT DISTINCT ON (1)
ts_round(timestamp, 300) AS interval_timestamp
, min(price) OVER w AS min_price
, max(price) OVER w AS max_price
, first_value(price) OVER w AS first_price
, last_value(price) OVER w AS last_price
FROM trades
WINDOW w AS (PARTITION BY ts_round(timestamp, 300) ORDER BY timestamp
ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING)
ORDER BY 1 DESC;
定义"首先"和"最后"根据{{1}},此列需要是唯一的,或者查询是不明确的,并且您可以从相同的同行中获取任意选择。
与自定义窗口框架的解释相似的答案:
按顺序编号引用的说明:
除此之外:不要使用"时间戳"作为标识符。它是一个基本类型名称,容易出错。