Question

我有两张桌子 - 支票和政策。以下是结构。为清楚起见，这是最低限度的结构

表名：检查

列： ChequeId。支票号码，量， LASTUPDATED

表名：政策

列 PolicyId，保单号码， ChequeId，量， LASTUPDATED

我想要一个回复

的查询

ChequeNumber,PolicyId,ChequeAmount,PolicyAmount,Difference

一个检查可以映射到多个策略（一对多关系）现在，如果检查匹配说2个政策并且这两个政策的金额总和大于支票金额，我应该看到差异，但仅限于第二个政策。它假设第一个政策完全匹配。（也许使用最后更新的列??）所以输出将是

ChequeNumber  PolicyNumber  ChequeAmount   PolicyAmount    Difference    
   1               1             200          100           0 
   1               2             200          200           100

以下是我所写的内容

SELECT chequeNumber AS chequeNumber
      ,COALESCE(p.policyNumber, '') AS PolicyNumber
      ,c.amount AS chequeamount
      ,p.Amount As PolicyAmount
      ,(c.Amount) - SUM(p.Amount) OVER (PARTITION BY c.ChequeID) AS Difference
FROM Cheque c 
LEFT JOIN Policy AS p 
    ON p.ChequeId=c.ChequeId 
GROUP BY chequeNumber, policyNumber,c.amount,p.Amount,c.ChequeID

这给了我两个行（下表）的差异，而不仅仅是映射的最后一个策略。

ChequeNumber  PolicyNumber  ChequeAmount   PolicyAmount    Difference    
   1               1             200          100           -100 
   1               2             200          200           -100

我正在使用SQL 2008 R2。

Answer 1

由于您使用的是SQL Server 2008，因此对WINDOW函数的支持有限，因此您需要自联接：

WITH DATA AS
(
    SELECT chequeNumber AS chequeNumber
          ,COALESCE(p.policyNumber, '') AS PolicyNumber
          ,c.amount AS chequeamount
          ,p.Amount As PolicyAmount
          ,P.MovingSum
    FROM Cheque c 
    LEFT JOIN  (SELECT P1.PolicyId
                      ,P1.PolicyNumber
                      ,P1.ChequeId
                      ,P1.Amount
                      ,P1.Amount + COALESCE(P2.Amount, 0) AS MovingSum
                FROM Policy AS P1
                LEFT JOIN Policy AS P2
                    ON P1.ChequeId = P2.ChequeId
                    AND P1.PolicyId > P2.PolicyId
                    AND P1.PolicyNumber > P2.PolicyNumber) AS p 
        ON p.ChequeId = c.ChequeId
    GROUP BY chequeNumber, policyNumber, c.amount, p.Amount, c.ChequeID, p.MovingSum
)
SELECT chequeNumber
      ,PolicyNumber
      ,chequeamount
      ,PolicyAmount
      ,CASE WHEN MovingSum > PolicyAmount THEN MovingSum - chequeamount ELSE 0 END AS Difference
FROM DATA;

Answer 2

如果我理解正确，你需要计算它们之间的差异保单金额 - （支票金额 - 已分配给以前保单金额的金额）考虑到分配是以policynumber顺序，这应该工作：

SELECT chequeNumber AS chequeNumber
      ,COALESCE(p.policyNumber, '') AS PolicyNumber
      ,c.amount AS chequeamount
      ,p.Amount As PolicyAmount
      ,p.amount - 
      CASE WHEN
      (c.Amount - (SELECT SUM(p1.amount) FROM cheque c1 LEFT JOIN policy p1 ON p1.chequeid=c1.chequeid AND p1.policynumber < p.policynumber)) < 0   THEN 0
      ELSE  (c.Amount - (SELECT SUM(p1.amount) FROM cheque c1 LEFT JOIN policy p1 ON p1.chequeid=c1.chequeid AND p1.policynumber < p.policynumber)) END Difference
FROM Cheque c 
LEFT JOIN Policy AS p 
    ON p.ChequeId=c.ChequeId 
GROUP BY chequeNumber, policyNumber,c.amount,p.Amount,c.ChequeID

SQL DIfference的两列

2 个答案: