Question

我在查询中有一个逻辑，用于确定通过的天数，不包括周末。有两种可能的开始日期 - 原始收货日期或重新提交日期（如果存在）。我可以使用以下CASE语句

正确计算

  CASE WHEN [ResubmitReceivedDate] IS NULL THEN
  (SELECT
        (DATEDIFF(dd, [OriginalReceivedDate] , [AnalysisDate]) + 1)
        -(DATEDIFF(wk,[OriginalReceivedDate] , [AnalysisDate]) * 2)
        -(CASE WHEN DATENAME(dw, [OriginalReceivedDate] ) = 'Sunday' THEN 1 ELSE 0 END)
        -(CASE WHEN DATENAME(dw, [AnalysisDate]) = 'Saturday' THEN 1 ELSE 0 END) 
    )
    ELSE
    (SELECT
        (DATEDIFF(dd, [ResubmitReceivedDate], [AnalysisDate]) + 1)
        -(DATEDIFF(wk, [ResubmitReceivedDate], [AnalysisDate]) * 2)
        -(CASE WHEN DATENAME(dw, [ResubmitReceivedDate]) = 'Sunday' THEN 1 ELSE 0 END)
        -(CASE WHEN DATENAME(dw, [AnalysisDate]) = 'Saturday' THEN 1 ELSE 0 END) 
    )

但是，有些情况下[AnalysisDate]位于[ResubmitReceivedDate]之前，在这些情况下，即使[OriginalReceivedDate]存在，仍应使用[ResubmitReceivedDate]。

如何将此逻辑添加到上述CASE语句中？

Answer 1

似乎最简单的解决方案就是添加另一个When条件。像这样：

WHEN DateDiff(day, [ResubmitReceivedDate], [AnalysisDate]) > -1 THEN
    (Select
        (DATEDIFF(day, [OriginalReceivedDate] , [AnalysisDate]) + 1)
        -(DATEDIFF(week,[OriginalReceivedDate] , [AnalysisDate]) * 2)
        -(CASE WHEN DATENAME(weekday, [OriginalReceivedDate] ) = 'Sunday' THEN 1 ELSE 0 END)
        -(CASE WHEN DATENAME(weekday, [AnalysisDate]) = 'Saturday' THEN 1 ELSE 0 END)
    )

哪个会成为你的最终案例

Case
     WHEN [ResubmitReceivedDate] IS NULL THEN
        (Select
            (DATEDIFF(day, [OriginalReceivedDate] , [AnalysisDate]) + 1)
            -(DATEDIFF(week,[OriginalReceivedDate] , [AnalysisDate]) * 2)
            -(CASE WHEN DATENAME(weekday, [OriginalReceivedDate] ) = 'Sunday' THEN 1 ELSE 0 END)
            -(CASE WHEN DATENAME(weekday, [AnalysisDate]) = 'Saturday' THEN 1 ELSE 0 END)
        )
     WHEN DateDiff(day, [ResubmitReceivedDate], [AnalysisDate]) < -1 THEN
        (Select
            (DATEDIFF(day, [OriginalReceivedDate] , [AnalysisDate]) + 1)
            -(DATEDIFF(week,[OriginalReceivedDate] , [AnalysisDate]) * 2)
            -(CASE WHEN DATENAME(weekday, [OriginalReceivedDate] ) = 'Sunday' THEN 1 ELSE 0 END)
            -(CASE WHEN DATENAME(weekday, [AnalysisDate]) = 'Saturday' THEN 1 ELSE 0 END)
        )
    Else
        (SELECT
            (DATEDIFF(day, [ResubmitReceivedDate], [AnalysisDate]) + 1)
            -(DATEDIFF(week, [ResubmitReceivedDate], [AnalysisDate]) * 2)
            -(CASE WHEN DATENAME(weekday, [ResubmitReceivedDate]) = 'Sunday' THEN 1 ELSE 0 END)
            -(CASE WHEN DATENAME(weekday, [AnalysisDate]) = 'Saturday' THEN 1 ELSE 0 END) 
        )
End

具有日期条件逻辑的CASE表达式

1 个答案: