如何上传多个文件,创建文件夹并将文件放在那里PHP

时间:2015-01-14 15:53:39

标签: php forms

好的,我可以成功上传1个文档,让它在主文件夹中创建一个新文件夹。然后将文件放在那里。

但是我无法将多个文件写入同一个文件夹。

我想上传2个文档,如下所示:

docs / 1 /然后是这里的文件。

它看起来像什么:

文档/ 1

HTML:

   <form action="upload.php" method="post" enctype="multipart/form-data">
        Select image to upload:<br/>
        <input type="file" name="fileToUpload" id="fileToUpload"><br/>
        <input type="file" name="fileToUpload" id="fileToUpload"><br/>
        <input type="submit" value="Upload Image" name="submit">
    </form>

PHP:

<?php
$number = 1;
$target_dir = "docs/";
$new = mkdir($target_dir . $number . "/");
$target_file = $target_dir . $number . "/";

$uploadOk = 1;
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
// Check if image file is a actual image or fake image

    // Check if file already exists
    if (file_exists($target_file)) {
        echo "Sorry, file already exists.";
        $uploadOk = 0;
    }
    // Check file size
    if ($_FILES["fileToUpload"]["size"] > 500000) {
        echo "Sorry, your file is too large.";
        $uploadOk = 0;
    }
    // Allow certain file formats
    if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg"
    && $imageFileType != "gif" ) {
        echo "Sorry, only JPG, JPEG, PNG & GIF files are allowed.";
        $uploadOk = 0;
    }
    // Check if $uploadOk is set to 0 by an error
    if ($uploadOk == 0) {
        echo "Sorry, your file was not uploaded.";
    // if everything is ok, try to upload file
    } else {
        foreach($_FILES['fileToUpload']['name'] as $file => $uploaded_file){
            move_uploaded_file($_FILES['fileToUpload']['tmp_name'], $target_file . $uploaded_file);
        }
}
?>

任何想法?

编辑工作:        

        <input type="file" name="pictures[]" /><br/>
        <input type="file" name="pictures[]" /><br/>
        <input type="file" name="pictures[]" /><br/>
        <input type="submit" value="Send" />

    </form>

$target_dir = "docs/";
$dir=glob($target_dir."/*",GLOB_ONLYDIR);
$number = count($dir) + 1;
$new = mkdir($target_dir . $number . "/");
$target_file = $target_dir . $number . "/";


foreach ($_FILES["pictures"]["name"] as $key => $Name) 
{
        $tmp_name = $_FILES["pictures"]["tmp_name"][$key];
        $name = $_FILES["pictures"]["name"][$key];
        move_uploaded_file($tmp_name, $target_file . "$name");
}

1 个答案:

答案 0 :(得分:1)

首先将文件输入更改为(注意所有元素的id应该是唯一的,以避免javascript问题):

<input type="file" name="fileToUpload[]" id="fileToUpload_0">

由于您要上传文件数组。

foreach($_FILES['fileToUpload'][$name] as $index=>$uploaded_file) {
    move_uploaded_file(
          $_FILES['fileToUpload']['tmp_name'][$index], 
         $target_file.$uploaded_file);
}

更新:在语言和文件处理逻辑中暂时混合。