Question

我是python的新手，我在下面的代码中遇到了简单的问题代码应该给出结果＆＃39; x100＆＃39;虽然它是＆＃39; x10＆＃39;和＆＃39; x100＆＃39;。如何获得预期的结果。

test_list=['x10','x50','x100']
text='this text has x100 only'
for i in test_list:
    if  text.find(i)!=-1:
        print "found "+i 
>>> 
found x10
found x100
>>>

Answer 1

更简单的方法是

test_list=['x10','x50','x100']
text='this text has x100 only'
for i in test_list:
    if  i in text.split():
        print "found "+i

要检测

test_list=['x10','x50','x100']
test_list= sorted(test_list,key = lambda x: len(x), reverse = True)
text='this text has x100n only'
import re
a = re.search("|".join(test_list),text)
if a:
    print "Found",a.group()

Answer 2

您可以使用.split()查找它是否在单词列表中：

>>> test_list=['x10','x50','x100']
>>> text='this text has x100 only'
>>> for i in test_list:
...   if i in text.split():
...     print "found",i
...
found x100

Answer 3

您可以使用此简单列表解析来查找所有实例。额外奖励：它只计算一次拆分。

def f(s, lst):
    return [item for item in lst if item in s.split()]

测试它：

>>> test_list=['x10','x50','x100']
>>> text='this text has x100 only'
>>> f(text, test_list)
['x100']

python在字符串中查找子字符串

3 个答案: