Question

我有两个datetimepickers。所以我希望得到所选值之间的星期几。

示例：date1 = 14/1/2015和date2 = 17/1/2015

所以结果应该是：days = Wed. Thu. Fri. Sat.

Answer 1

您希望在两个日期之间获得所有DayOfWeek的{{1}}个？

DateTime

您需要添加int daysDiff = (date2 - date1).Days; List<DayOfWeek> days = Enumerable.Range(0, daysDiff + 1) // +1 because you want to include start and end date .Select(d => date1.AddDays(d).DayOfWeek) .ToList();

Answer 2

您可以轻松地迭代DateTime值，例如;

var dt1 = new DateTime(2015, 1, 14);
var dt2 = new DateTime(2015, 1, 17);
while (dt2 >= dt1)
{
    Console.WriteLine(dt1.DayOfWeek);
    dt1 = dt1.AddDays(1);
}

结果将是;

Wednesday
Thursday
Friday
Saturday

如果您希望将abbreviated day names改为Wed, Thu, Fri, Sat，则可以将"ddd" custom format specifier与基于英语的文化（如InvariantCulture）一样使用;

var dt1 = new DateTime(2015, 1, 14);
var dt2 = new DateTime(2015, 1, 17);
while (dt2 >= dt1)
{
    Console.WriteLine(dt1.ToString("ddd", CultureInfo.InvariantCulture));
    dt1 = dt1.AddDays(1);
}

Answer 3

另一种替代方案，包括非常规使用for循环和yield return语句：

void Main()
{
    var daysOfWeek = DaysBetween(
        new DateTime(2015, 1, 14), 
        new DateTime(2015, 1, 17));

    Console.WriteLine(
        String.Join(", ", daysOfWeek.Select(d => d.ToString().Substring(0, 3))));

    // prints: Wed, Thu, Fri, Sat
}

IEnumerable<DayOfWeek> DaysBetween(DateTime start, DateTime end)
{
    for (var dateTime = start; dateTime <= end; dateTime = dateTime.AddDays(1))
    {
        yield return dateTime.DayOfWeek;
    }
}

获取两个选定日期之间的星期几

3 个答案: