Question

我有一个数组对象：

var checkin_status = [{
    "startdate":"2015-01-08",
    "totaldays":"4",  
    "roadmap":[
        { "gifttype": "stars", "quantity": 100, "day": 1},
        { "gifttype": "stars", "quantity": 500, "day": 3},
        { "gifttype": "stars", "quantity": 1000, "day": 10},
        { "gifttype": "stars", "quantity": 1200, "day": 20},
        { "gifttype": "stars", "quantity": 2200, "day": 30},
    ]
}];

var checkin_info = checkin_status[0].roadmap;
var total = 0;
for (var i = 0; i < checkin_info.length; ++i){
    total += checkin_info[i].day;
    alert(total);
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

到目前为止，我尝试使用此代码，我需要添加下一个索引号的对象，例如：day 1 + day 3 = 4，然后是{{1 }} + 3 = 10等等。我需要的输出就像13。

知道怎么做吗？

Answer 1

这是循环答案：

＆＃13;

var checkin_status = [{
  "startdate": "2015-01-08",
  "totaldays": "4",
  "roadmap": [{
    "gifttype": "stars",
    "quantity": 100,
    "day": 1
  }, {
    "gifttype": "stars",
    "quantity": 500,
    "day": 3
  }, {
    "gifttype": "stars",
    "quantity": 1000,
    "day": 10
  }, {
    "gifttype": "stars",
    "quantity": 1200,
    "day": 20
  }, {
    "gifttype": "stars",
    "quantity": 2200,
    "day": 30
  }, ]
}];

var checkin_info = checkin_status[0].roadmap;
var output = [];
for (var i = 1; i < checkin_info.length; ++i) {
  output.push(checkin_info[i - 1].day + checkin_info[i].day);
}
console.log(output);

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>

＆＃13;

以下是每个答案的jquery：

＆＃13;

var checkin_status = [{
  "startdate": "2015-01-08",
  "totaldays": "4",
  "roadmap": [{
    "gifttype": "stars",
    "quantity": 100,
    "day": 1
  }, {
    "gifttype": "stars",
    "quantity": 500,
    "day": 3
  }, {
    "gifttype": "stars",
    "quantity": 1000,
    "day": 10
  }, {
    "gifttype": "stars",
    "quantity": 1200,
    "day": 20
  }, {
    "gifttype": "stars",
    "quantity": 2200,
    "day": 30
  }, ]
}];
var checkin_info = checkin_status[0].roadmap;
var output = [];
$.each(checkin_status[0].roadmap, function(index, obj) {
  if (index === 0)
    return;
  output.push(checkin_info[index - 1].day + obj.day);
});
console.log(output);

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>

＆＃13;

Answer 2

试试这个：

array  = checkin_status[0].roadmap.map(function(d){return d.day})
a=0; b=[];
array.forEach(function(d){
    if(a != 0){
         b.push(a+d)};
         a = d
    }
)
console.log(b)

Answer 3

    var checkin_status = [{
      "startdate": "2015-01-08",
      "totaldays": "4",
      "roadmap": [{
        "gifttype": "stars",
        "quantity": 100,
        "day": 1
      }, {
        "gifttype": "stars",
        "quantity": 500,
        "day": 3
      }, {
        "gifttype": "stars",
        "quantity": 1000,
        "day": 10
      }, {
        "gifttype": "stars",
        "quantity": 1200,
        "day": 20
      }, {
        "gifttype": "stars",
        "quantity": 2200,
        "day": 30
      }, ]
    }];

    var checkin_info = checkin_status[0].roadmap;
    var total = 0;
    for (var i = 1; i < checkin_info.length; ++i){
        total = checkin_info[i-1].day + checkin_info[i].day;
         if (typeof total !== 'undefined'){
           console.log(total);
         }
    }

在数组对象中查找中间数字

3 个答案: