Question

我正在尝试保存并加载一些值和名称作为一个小项目，但我有一些负载部分的麻烦我使用PYTHON 3.4和tkinter创建4个texbox，2个用于名称，2个用于值，2个按钮用于保存和加载我放在这些文本框中的内容我可以在这些文本框中写任何东西，所以我说我放

apple 20

橙色40

所以在我的前2个文本框中，我在另外2个中有2个字符串和整数所以我的代码是

import time
import serial
import sys
import os
import tkinter as tk
from tkinter import ttk
from tkinter import *
from tkinter import messagebox
from tkinter import filedialog
from tkinter.filedialog import askopenfilename
from tkinter.filedialog import asksaveasfilename
from tkinter.messagebox import showerror
try:
  import Tkinter              # Python 2
  import ttk
except ImportError:
  import tkinter as Tkinter   # Python 3
  import tkinter.ttk as ttk
mGui = Tk()
mGui.title("trying")
mGui.geometry('1250x650+10+10')
def mSave():
  filename = asksaveasfilename(defaultextension='.txt',filetypes = (('Text files', '*.txt'),    ('Python files', '*.py *.pyw'),('All files', '*.*')))
  if filename is None:
    return
  file = open (filename, mode = 'w')
  NameVal_1 = name1.get()
  NameVal_2 = name2.get()
  Vol_Val_1 = value1.get()
  Vol_Val_2 = value2.get()

  all =   (NameVal_1 + "," + (str(Vol_Val_1)) + ","
         + NameVal_2 + "," + (str(Vol_Val_2)))
  file.write(all)
  file.close()

def mLoad():
  filenamel = askopenfilename()
  if filenamel is None:
    return
  (NameVal_1, Vol_Val_1,
   NameVal_2, Vol_Val_2)   = (x.split(",")[3] for x in filenamel)

  name1.set(NameVal_1)
  name2.set(NameVal_2)
  value1.set(Vol_Val_1)
  value2.set(Vol_Val_2)
  file.close()

value1 = IntVar()
value2 = IntVar()
name1 = StringVar()
name2 = StringVar()

mButtonSave = Button(mGui, text = "Save Data", command = mSave, fg = 'Red').place(x=550,y=80)
mButtonLoad = Button(mGui, text = "Load Data", command = mLoad, fg = 'Red').place(x=550,y=110)

tText1 = Entry(mGui, textvariable = name1).place(x=10,y=80)
tText2 = Entry(mGui, textvariable = name2).place(x=10,y=100)
vText1 = Entry(mGui, textvariable = value1).place(x=200,y=80)
vText2 = Entry(mGui, textvariable = value2).place(x=200,y=100)

保存工作正常，我可以创建一个显示

的存档.txt

apple,20,orange,40

但是当我尝试将这些值放在文本框中时，我不能 python说

IndexError: list index out of range

我只想要，当四个文本框为空时我按下按钮Load，将苹果放入文本框1，文本框2中的20，文本框3中的橙色和文本框4中的40再次

我该怎么办？任何帮助，请

已编辑

这是最终的代码，谢谢

import time
import serial
import sys
import os
import tkinter as tk
from tkinter import ttk
from tkinter import *
from tkinter import messagebox
from tkinter import filedialog
from tkinter.filedialog import askopenfilename
from tkinter.filedialog import asksaveasfilename
from tkinter.messagebox import showerror
try:
  import Tkinter              # Python 2
  import ttk
except ImportError:
  import tkinter as Tkinter   # Python 3
  import tkinter.ttk as ttk
mGui = Tk()
mGui.title("trying")
mGui.geometry('1250x650+10+10')
def mSave():
  filename = asksaveasfilename(defaultextension='.txt',filetypes = (('Text files', '*.txt'),    ('Python files', '*.py *.pyw'),('All files', '*.*')))
  if filename is None:
    return
  file = open (filename, mode = 'w')
  NameVal_1 = name1.get()
  NameVal_2 = name2.get()
  Vol_Val_1 = value1.get()
  Vol_Val_2 = value2.get()

  all =   (NameVal_1 + "," + (str(Vol_Val_1)) + ","
         + NameVal_2 + "," + (str(Vol_Val_2)))
  file.write(all)
  file.close()

def mLoad():
  filenamel = askopenfilename()
  if filenamel is None:
    return
  with open(filenamel, 'r') as f:
    x = f.readline()  # read the first line
    (NameVal_1, Vol_Val_1,  NameVal_2, Vol_Val_2) = x.split(",")  

  name1.set(NameVal_1)
  name2.set(NameVal_2)
  value1.set(Vol_Val_1)
  value2.set(Vol_Val_2)
  filename.close()

value1 = IntVar()
value2 = IntVar()
name1 = StringVar()
name2 = StringVar()

mButtonSave = Button(mGui, text = "Save Data", command = mSave, fg = 'Red').place(x=550,y=80)
mButtonLoad = Button(mGui, text = "Load Data", command = mLoad, fg = 'Red').place(x=550,y=110)

tText1 = Entry(mGui, textvariable = name1).place(x=10,y=80)
tText2 = Entry(mGui, textvariable = name2).place(x=10,y=100)
vText1 = Entry(mGui, textvariable = value1).place(x=200,y=80)
vText2 = Entry(mGui, textvariable = value2).place(x=200,y=100)

Answer 1

filenamel = askopenfilename()仅为您提供文件路径。它实际上并没有读取文件。因此，您需要打开它并阅读。此外，如果文件中只有一行，如示例所示，此(x.split(",")[3] for x in filenamel)将不起作用，因为它迭代文件路径中的字母，而不是文件中的行。您应该在mLoad()中执行以下操作：

# open the file for reading
with open(filenamel, 'r') as f:
    x = f.readline()  # read the first line   

# split it by ',' and assing to appropriate variables.
(NameVal_1, Vol_Val_1,  NameVal_2, Vol_Val_2) = x.split(",")

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1 个答案: