Question

下面是我的R代码，它采用向量a并返回向量b。向量b应该是具有特定格式的向量a的唯一标识符。请注意，a的所有相同数字彼此相邻排序。

a <- c(1, 1, 1, 2, 2, 2, 3, 4, 5, 6, 6, 6, 6, 7, 8, 9, 9)
b <- NULL


for(i in 5:length(a)){
        if (a[i] == a[i - 1] & a[i] == a[i - 2] & a[i] == a[i - 3] & a[i] == a[i - 4])
            b[i] <- paste(a[i], "-", 4, sep="")
        else if (a[i] == a[i - 1] & a[i] == a[i - 2] & a[i] == a[i - 3])
            b[i] <- paste(a[i], "-", 3, sep="")
        else if (a[i] == a[i - 1] & a[i] == a[i - 2])
            b[i] <- paste(a[i], "-", 2, sep="")
        else if (a[i] == a[i - 1])
            b[i] <- paste(a[i], "-", 1, sep="")
        else 
            b[i] <- paste(a[i], "-", 0, sep="")
}

#The first 4 values in vector b have to manually entered 
#because the for loop checks up to 4 consecutive numbers in a
b[1] <- "1-0" 
b[2] <- "1-1"
b[3] <- "1-2"
b[4] <- "2-0"

b

上面的代码根据需要返回b，但是，如果向量a具有多于4个相同的连续数，则for循环将产生包含一些相同元素的b。如何改进这种for循环，以便可以为任何数量的相同连续数字赋予适当的唯一标识符。

我正在考虑使用某种嵌套的for循环，但是如何在if语句中完成呢？

Answer 1

这可能会取代您当前的循环。 rle()用于为a的每个唯一元素构造一个序列，从零开始。然后我们可以paste()与-分隔符一起paste(a, sequence(rle(a)$lengths) - 1, sep = "-") # [1] "1-0" "1-1" "1-2" "2-0" "2-1" "2-2" "3-0" "4-0" "5-0" "6-0" "6-1" # [12] "6-2" "6-3" "7-0" "8-0" "9-0" "9-1"。

与{{1}}

的输出相同

Answer 2

使用ave和paste，我现在意识到这只是@ RichardScriven答案的变体：

paste(a, ave(a,a,FUN=seq_along) - 1, sep="-")
# [1] "1-0" "1-1" "1-2" "2-0" "2-1" "2-2" "3-0" "4-0" "5-0" "6-0" "6-1"
#[12] "6-2" "6-3" "7-0" "8-0" "9-0" "9-1"

Answer 3

# If you are sure the different groups are really sorted, this will work:
b <- tapply(1:length(a), a, FUN = function(x) (1:length(x)) -1 )
b <- paste(a, unlist(b), sep = "-")

R编程：这个for循环的更灵活的版本

3 个答案: