Question

所以我有这个代码，我很困惑。我需要先按最早的日期排序，但我找不到任何难以解决的问题？

<?php require_once('header.php'); ?>

    <div class="nav1">
            <p>Upcoming Expiration Dates</p>
    </div>

<div class="data"   style=" width:80%; margin:-31px auto auto 89px;  ">

            <ul>
                    <li style="font-size: 20px; background-color:#9E9494;">Name</li>
            </ul>
            <ul>
                    <li style="font-size: 20px; background-color:#9E9494;">Expire Date</li>
            </ul>

            <ul>
                    <li style="font-size: 20px; background-color:#9E9494;">License Type</li>
            </ul>
<?php
/* Start Registered_Nurses */
$select="SELECT * FROM registered_nurses INNER JOIN licenses ON registered_nurses.id= licenses.id where professional_license BETWEEN '$cdate' AND DATE_ADD('$cdate', INTERVAL 135675 DAY) and '$cdate' ";
$m=mysql_query($select);
while($f=mysql_fetch_array($m))
{
    if($f[6]>=$cdate)
    {
    echo "<ul>";
        echo "<li style='background-color:#f1f1f1; '>";
        echo "<a href='upcom_nurse_edit.php?id=$f[0]&lt=professional license' style='color:#6C89D1;'>$f[1]</a>";
        echo "</li>";
        echo "<li style='background-color:#f1f1f1; color:#6C89D1; '>";
        echo $f[6];
        echo "</li>";
        echo "<li style='background-color:#f1f1f1; color:#6C89D1;'>";
        echo "professional license";
        echo "</li>";
    echo "</ul>";
    }   
}
$select="SELECT * FROM registered_nurses INNER JOIN licenses ON registered_nurses.id= licenses.id where professional_license BETWEEN '$cdate' - INTERVAL 135675 DAY AND '$cdate' ";
$m=mysql_query($select);

while($f=mysql_fetch_array($m))
{
    if($f[6]<$cdate)
    {
    echo "<ul>";
        echo "<li style='background-color:#f1f1f1;'>";
        echo "<a href='upcom_nurse_edit.php?id=$f[0]&lt=professional license' style='color:red;'>$f[1]</a>";
        echo "</li>";
        echo "<li style='background-color:#f1f1f1; color:red; '>";
        echo $f[6];
        echo "</li>";
        echo "<li style='background-color:#f1f1f1; color:red;'>";
        echo "professional license";
        echo "</li>";
    echo "</ul>";
    }

}

$select1="SELECT * FROM registered_nurses INNER JOIN licenses ON registered_nurses.id= licenses.id where license_verification BETWEEN '$cdate' AND DATE_ADD('$cdate', INTERVAL 135675 DAY) and '$cdate' ";
$m1=mysql_query($select1);
while($f1=mysql_fetch_array($m1))
{
    if($f1[7]>=$cdate)
    {

        echo "<ul>";
        echo "<li style='background-color:#cccccc;'>";
        echo "<a href='upcom_nurse_edit.php?id=$f1[0]&lt=License Verification' style='color:#6C89D1;'>$f1[1]</a>";
        echo "</li>";
        echo "<li style='background-color:#cccccc; color:#6C89D1;'>";
        echo $f1[7];
        echo "</li>";
        echo "<li style='background-color:#cccccc; color:#6C89D1;'>";
        echo "License Verification";
        echo "</li>";
    echo "</ul>";
    }
}
$select1="SELECT * FROM registered_nurses INNER JOIN licenses ON registered_nurses.id= licenses.id where license_verification BETWEEN '$cdate' - INTERVAL 135675 DAY AND '$cdate' ";
$m1=mysql_query($select1);
while($f1=mysql_fetch_array($m1))
{
    if($f1[7]<$cdate)
    {

        echo "<ul>";
        echo "<li style='background-color:#cccccc;'>";
        echo "<a href='upcom_nurse_edit.php?id=$f1[0]&lt=License Verification' style='color:red;'>$f1[1]</a>";
        echo "</li>";
        echo "<li style='background-color:#cccccc; color:red;'>";
        echo $f1[7];
        echo "</li>";
        echo "<li style='background-color:#cccccc; color:red;'>";
        echo "License Verification";
        echo "</li>";
    echo "</ul>";
    }
}

$select2="SELECT * FROM registered_nurses INNER JOIN licenses ON registered_nurses.id= licenses.id where cpr BETWEEN '$cdate' AND DATE_ADD('$cdate', INTERVAL 135675 DAY) and '$cdate' ";
$m2=mysql_query($select2);
while($f2=mysql_fetch_array($m2))
{
    if($f2[8]>=$cdate)
    {
    echo "<ul>";
        echo "<li style='background-color:#f1f1f1;'>";
        echo "<a href='upcom_nurse_edit.php?id=$f2[0]&lt=CPR' style='color:#6C89D1;' >$f2[1]</a>";
        echo "</li>";
        echo "<li style='background-color:#f1f1f1; color:#6C89D1;'>";
        echo $f2[8];
        echo "</li>";
        echo "<li style='background-color:#f1f1f1; color:#6C89D1;'>";
        echo "CPR";
        echo "</li>";
    echo "</ul>";
    }
}

Answer 1

这是一大堆代码...

如果您的问题是如何以特定顺序从数据库查询中返回一组行...

在SQL文本的 ORDER BY 子句中指定所需的序列。

假设professional_license是DATE或DATETIME列，并且您希望首先使用该列中最旧的值返回查询中的行，那么您的查询将看起来像这样：

 SELECT ...
   FROM ...
  WHERE ...
  ORDER BY professional_license ASC

如果您希望行按相反的顺序，请将ASC替换为DESC。可以在ORDER BY子句中指定多个表达式...如果两行具有professional_license的相同值，则下一个表达式将用于确定匹配值为professional_license的行的顺序将被退回。例如：

  ORDER BY professional_license ASC, name ASC

对您的其他查询执行相同的模式，在ORDER BY子句中指定您希望结果集“按顺序排列”的表达式。

（如果你问的是另一个问题，那就不清楚了。）

Answer 2

HI在您的查询中，只使用orderby子句作为ORDER BY date asc

按日期排序表字段从最旧到最新

2 个答案: