Question

好的，我有一个带有1个输入和提交按钮的表单。现在我使用if / else语句为该输入做出三个可接受的答案。是的，不，或其他任何东西。这个if / else工作的东西是代码在加载页面后立即踢出else函数。我希望在用户输入之前没有任何内容，然后它会显示三个答案中的一个。

Welcome to your Adventure! You awake to the sound of rats scurrying  around your dank, dark cell. It takes a minute for your eyes to adjust to your surroundings. In the corner of the room you see what looks like a rusty key.
<br/>
Do you want to pick up the key?<br/>


<?php

//These are the project's variables.

$text2 = 'You take the key and the crumby loaf of bread.<br/>';

$text3 = 'You decide to waste away in misery!<br/>';

$text4 = 'I didnt understand your answer. Please try again.<br/>';

$a = 'yes';

$b = 'no';


// If / Else operators.

if(isset($_POST['senddata'])) {

    $usertypes = $_POST['name'];

}

if ($usertypes == $a){

    echo ($text2);
}

elseif ($usertypes == $b){

    echo ($text3);
}

else {

    echo ($text4);
}

?>

<form action="phpgametest.php" method="post">
         <input type="text" name="name" /><br>
         <input type="submit" name="senddata" /><br>
</form>

Answer 1

只需在设置POST值时调用代码即可。这样它只会在提交表单时执行代码（设置为$_POST['senddata']）：

if(isset($_POST['senddata'])) {

    $usertypes = $_POST['name'];

    if ($usertypes == $a){

        echo ($text2);
    }

    elseif ($usertypes == $b){

        echo ($text3);
    }

    else {
        echo ($text4);
    }
}

Answer 2

只需将验证放在第一个if语句中，如下所示：

if(isset($_POST['senddata'])) {

    $usertypes = $_POST['name'];


    if ($usertypes == $a) {
        echo ($text2);

    } elseif ($usertypes == $b) {
        echo ($text3);

    }  else {
        echo ($text4);
    }

}

Answer 3

当您加载页面时，浏览器正在发出GET请求，当您提交表单时，浏览器正在发出POST请求。您可以使用以下方式检查提出的请求：

if ($_SERVER['REQUEST_METHOD'] === 'POST') {
  // Your form was submitted
}

将它放在您的表单处理代码周围，以防止它在GET请求上执行。

PHP If / Else语句直接转到Else而不等待表单输入

3 个答案: