我试图在bash脚本中启动多个命令,但等待它们完成
它看起来像这样:
A &
B &
C &
D
不幸的是,我不知道哪些过程会先完成。但是在完成所有过程后我需要完整的脚本。
就像我尝试过的新秀一样:
(A &
B &
C &
D) && E
不幸的是E
仅在D
完成后执行。如果我能在A - D执行官之后得到E
,我想要它
希望总结问题。
由于
答案 0 :(得分:6)
A &
B &
C &
D &
wait
E
来自help
列表:
wait: wait [-n] [id ...] Wait for job completion and return exit status. Waits for each process identified by an ID, which may be a process ID or a job specification, and reports its termination status. If ID is not given, waits for all currently active child processes, and the return status is zero. If ID is a a job specification, waits for all processes in that job's pipeline. If the -n option is supplied, waits for the next job to terminate and returns its exit status. Exit Status: Returns the status of the last ID; fails if ID is invalid or an invalid option is given.
答案 1 :(得分:0)
wait(1)
是规范解决方案,但过去我使用了q& d解决方案:
( A & B & C & D & ) | cat; E