Question

我已经在javascript上创建了一个测验，一旦用户回答4/6或更正确，他们就会被要求提供名字，姓氏，然后给出随机的4位数代码。我遇到问题的部分是仅创建FirstName和LastName字母，也不允许和清空提示。

任何人都知道我如何实现正则表达式？

任何人都可以提供帮助吗？

function getAnswers(){         

var amountCorrect = 0;  

for(var i = 1; i <= 10; i++) {

    var radios = document.getElementsByName('q'+i);

    for(var j = 0; j < radios.length; j++){

        var radio = radios[j];

        if(radio.value == "1" && radio.checked) {
            amountCorrect++;
        }
    }
}   

alert("Correct number of answers: " + amountCorrect + " / 6");

if (amountCorrect <= 3){
    alert("You have not passed on this occasion. You will now be taken back to the homepage.");
    window.history.go(-1); // Go back a step
}
else{
    var firstname = prompt("Please enter your first name.");
    var lastname = prompt("Please enter your last name.");
    alert("Your login Code for the store is: " + firstname.substring(1, 0) + lastname.substring(1, 0) + (generateCode())); // Do the generateCode function
    close();    
  }
}

Answer 1

试试这个..

 var alphaExp = /^[a-zA-Z]+ [a-zA-Z]+$/;

    var firstname =prompt("Please enter your first name And Last Name","");
    if (firstname ==null || firstname =="")
    {
        alert("First and last name must be filled out!");
        location.reload(true);
    }
    else if (!firstname.matches(alphaExp))
    {
        alert("Name must contain letters only!")
        location.reload(true);
    }
   else{ // your code here.
      }

Answer 2

试试这个正则表达式：

^[A-Z][a-zA-Z]*$

此正则表达式匹配一串字母：

以字母A-Z
仅允许来自a-z和A-Z的字母
它不会匹配空行或任何其他字符。

Answer 3

/^[a-zA-Z]+$/

这适用于你。

javascript仅限信件

3 个答案: