Question

我有一个XSD，其属性为boolean，整数和元素为arraylist，如下所示，

            <?xml version="1.0" encoding="UTF-8"?>
            <xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema"
            xmlns:tns="http://www.template.com/project/v1/Repository"
            targetNamespace="http://www.template.com/project/v1/Repository"
            elementFormDefault="qualified"
            attributeFormDefault="unqualified"
            version="1.0"
            xml:lang="en">

            <xsd:complexType name="Response">
            <xsd:sequence>
                <xsd:element name="records" minOccurs="0" maxOccurs="unbounded" type="tns:Record" />
            </xsd:sequence>
                <xsd:attribute name="pageSize"              type="xsd:integer"   default="-1" />
                <xsd:attribute name="pageNumber"            type="xsd:integer"   default="1" />
            </xsd:complexType>

            <xsd:complexType name="Record">
            <xsd:sequence>
                <xsd:element name="column" minOccurs="0" maxOccurs="unbounded"  type="tns:Column" />
            </xsd:sequence>
            </xsd:complexType>

            <xsd:complexType name="Column">
            <xsd:attribute name="columnId" type="xsd:string" />
            <xsd:attribute name="columnValue" type="xsd:string" />
            </xsd:complexType>

现在我正在尝试添加一个包含对象列表（List<Object>）的元素。我无法在类型中添加Object类。那么如何在XSD中添加Object类。

            <xsd:element name="jsonrecords" minOccurs="0" maxOccurs="unbounded" type=" "  </xsd:element>

Answer 1

使用

<xsd:element name="jsonrecords" minOccurs="0" maxOccurs="unbounded" type="xsd:anySimpleType" />

它会产生类似

的东西

@XmlSchemaType(name = "anySimpleType")
protected List<Object> jsonrecords;

Answer 2

请参阅此处的映射图http://docs.oracle.com/javaee/5/tutorial/doc/bnazq.html，你可以使用应该转换为java.lang.Object的xsd：anySimpleType

在XSD架构中编写java.lang.Object

2 个答案: