Question

我正在使用此网址“http://test.ccsplinfo.com/services.svc/addSubscriber?userdetails={Email_Id:mishra.bn@gmail.com,FirstName:BN,LastName:MISHRA,MobileNumber:8285547554,Password:mypass}”从服务器获取数据。但我没有得到任何回应。当我只是复制和粘贴
这个URL到浏览器然后得到真正的response.it意味着url工作正常，但我在我的代码中得到错误我的代码在这里..

  NSMutableDictionary *dict=[[NSMutableDictionary alloc]init];
    [dict setObject:@"mishra.bn@gmail.com" forKey:@"Email_Id"];
    [dict setObject:@"BN" forKey:@"FirstName"];
    [dict setObject:@"MISHRA" forKey:@"LastName"];
    [dict setObject:@"8285547554" forKey:@"MobileNumber"];
    [dict setObject:@"mypass" forKey:@"Password"];

 NSString *PostUrl=@"http://test.ccsplinfo.com/services.svc/addSubscriber?userdetails=";

 NSError *serr;
    NSData *jsonData = [NSJSONSerialization
                        dataWithJSONObject:dict options:NSJSONWritingPrettyPrinted error:&serr];
    if (serr)
    {
        NSLog(@"Error generating json data for send dictionary...");
        NSLog(@"Error (%@), error: %@", dict, serr);
        return;
    }
    // Create request object
    NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:PostUrl]];

    request.HTTPMethod = @"POST";
    request.HTTPBody = jsonData;
    [request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
    [request setValue:@"application/json" forHTTPHeaderField:@"Accept"];

    [request setValue:
     [NSString stringWithFormat:@"%lu",
      (unsigned long)[jsonData length]] forHTTPHeaderField:@"Content-Length"];

    [NSURLConnection sendAsynchronousRequest:request
                                       queue:[NSOperationQueue mainQueue]
                           completionHandler:^(NSURLResponse *r, NSData *data, NSError *error)
     {
         if (!data)
         {
             NSLog(@"No data returned from server, error ocurred: %@", error);
             NSString *userErrorText = [NSString stringWithFormat:
                                        @"Error communicating with server: %@", error.localizedDescription];
             return;
         }
         NSError *deserr;
         NSDictionary *responseDict = [NSJSONSerialization
                                       JSONObjectWithData:data
                                       options:kNilOptions
                                       error:&deserr];

         NSLog(@" responseDict :%@", responseDict);

     }];


Thanks

Answer 1

您的要求看起来很好。我想你会低于错误

Error Domain=NSCocoaErrorDomain Code=3840

JSON text did not start with array or object and option to allow fragments not set.

这是因为服务器使用无效的JSON对象进行响应。

无法从我的网址在浏览器中运行良好的网络服务获得响应

1 个答案: