Question

我的字符串格式如下： -

"{\"A5\";\"A6\";\"A7\";\"varying number of params...\"}"

如何使用PHP将字符串转换为 A5, A6, A7, varying number of params...

我知道str_replace是一种方式，但我想知道用正则表达式做得更好吗？

Answer 1

如果您不需要正则表达式的强大功能，也可以将str_replace用于数组：

echo str_replace(array('"{\"', '\";\"', '\"}"'), array("", ", ", ""), $str);

- ＆GT; A5, A6, A7, varying number of params... test at eval.in

Answer 2

(?<=\\")[^\\;]+

试试这个。看看演示。

https://regex101.com/r/sH8aR8/53

$re = "/(?<=\\\\\")[^\\\\;]+/";
$str = "\"{\"A5\";\"A6\";\"A7\";\"varying number of params...\"}\"";

preg_match_all($re, $str, $matches);

详细说明：

NODE                     EXPLANATION
--------------------------------------------------------------------------------
  (?<=                     look behind to see if there is:
--------------------------------------------------------------------------------
    \\                       '\' 
--------------------------------------------------------------------------------
    "                        '"'
--------------------------------------------------------------------------------
  )                        end of look-behind
--------------------------------------------------------------------------------
  [^\\;]+                  any character except: '\\', ';' (1 or more
                       times (matching the most amount possible))

用于反序列化由分号分隔的字符串的正则表达式

2 个答案: