Question

我已经设置了这个登录表单，它将$ _POST数据转换为$ _SESSION数据。然后我使用此数据来确定用户是否应该登录，但它无法正常工作。我做错了什么？

***我检查了浏览器的cookie，并且存储了会话令牌（如果有帮助）

的login.php：

<?php session_start(); ?>

<form action="page.php" method="post">

        Username: <input type="text" name="username" value="" /><br />
        Password: <input type="password" name="password" value="" /><br />
        <br />
        <input type="submit" name="submit" value="Submit" />

        <?php

        if (isset($_POST['submit'])) {
            $username = $_POST['username'];
            $password = $_POST['password'];
            $submit = $_POST['submit'];

            $_SESSION['username'] = $username;
            $_SESSION['password'] = $password;
            $_SESSION['submit'] = $submit;
        }

        ?>

</form>

page.php文件：

<?php session_start(); ?>

<?php

        $username = isset($_SESSION["username"]) ? $_SESSION["username"] : "";
        $password = isset($_SESSION["password"]) ? $_SESSION["password"] : "";

        $submit = isset($_SESSION["submit"]) ? $_SESSION["submit"] : "";


        if(($username == "username") && ($password == "password") && ($submit == "Submit")) {
            echo "You are logged in";
        } else {
            echo "Denied access";
        }
?>

我在包含session_start（）;

的网页上收到此错误

enter image description here

根据this post，这是由Chrome引起的错误报告，但不会影响任何内容。

Answer 1

<form action="page.php" method="post">

    Username: <input type="text" name="username" value="" /><br />
    Password: <input type="password" name="password" value="" /><br />
    <br />
    <input type="submit" name="submit" value="Submit" />


 </form>

page.php文件

 <?php
    session_start();
    if (isset($_POST['submit'])) {
        $username = $_POST['username'];
        $password = $_POST['password'];
        $submit = $_POST['submit'];

        $_SESSION['username'] = $username;
        $_SESSION['password'] = $password;
        $_SESSION['submit'] = $submit;
    }
    $username = isset($_SESSION["username"]) ? $_SESSION["username"] : "";
    $password = isset($_SESSION["password"]) ? $_SESSION["password"] : "";

    $submit = isset($_SESSION["submit"]) ? $_SESSION["submit"] : "";


    if(($username == "username") && ($password == "password") && ($submit == "Submit"))        {
        echo "You are logged in";
    } else {
        echo "Denied access";
    }
?>

Answer 2

当您将表单submit上的操作发送到另一个页面page.php时。那么，为什么你在同一页面上获得表单数据呢？

请尝试此操作：

HTML表格：

<form action=page.php method="post">

    Username: <input type="text" name="username" value="" /><br />
    Password: <input type="password" name="password" value="" /><br />
    <br />
    <input type="submit" name="submit" value="Submit" />


 </form>

page.php：

 <?php
    session_start();
    if (isset($_POST['submit'])) {
        $username = $_POST['username'];
        $password = $_POST['password'];
        $submit = $_POST['submit'];

        $_SESSION['username'] = $username;
        $_SESSION['password'] = $password;
        $_SESSION['submit'] = $submit;
    }
    $username = isset($_SESSION["username"]) ? $_SESSION["username"] : "";
    $password = isset($_SESSION["password"]) ? $_SESSION["password"] : "";

    $submit = isset($_SESSION["submit"]) ? $_SESSION["submit"] : "";


    if(($username == "username") && ($password == "password") && ($submit == "Submit"))        {
        echo "You are logged in";
    } else {
        echo "Denied access";
    }
?>

Answer 3

在页面顶部添加session_start();并修复操作。

<?php session_start();?>
<form action="" method="post">

        Username: <input type="text" name="username" value="" /><br />
        Password: <input type="password" name="password" value="" /><br />
        <br />
        <input type="submit" name="submit" value="Submit" />

        <?php

        if (isset($_POST['submit'])) {
            $username = $_POST['username'];
            $password = $_POST['password'];
            $submit = $_POST['submit'];

            $_SESSION['username'] = $username;
            $_SESSION['password'] = $password;
            $_SESSION['submit'] = $submit;
            header('page.php');
        }

        ?>

</form>

和

<?php
        session_start();
        $username = isset($_SESSION["username"]) ? $_SESSION["username"] : "";
        $password = isset($_SESSION["password"]) ? $_SESSION["password"] : "";

        $submit = isset($_SESSION["submit"]) ? $_SESSION["submit"] : "";


        if(($username == "username") && ($password == "password") && ($submit == "Submit")) {
            echo "You are logged in";
        } else {
            echo "Denied access";
        }
?>

Answer 4

首先，您需要在表单页面中使用session_start()启动会话。此外，您还需要使用标头将会话发送到login.php。使用以下代码

<?php session_start();?>
<form action="" method="post">

        Username: <input type="text" name="username" value="" /><br />
        Password: <input type="password" name="password" value="" /><br />
        <br />
        <input type="submit" name="submit" value="Submit" />

        <?php

        if (isset($_POST['submit'])) {
            $username = $_POST['username'];
            $password = $_POST['password'];
            $submit = $_POST['submit'];

            $_SESSION['username'] = $username;
            $_SESSION['password'] = $password;
            $_SESSION['submit'] = $submit;
            header('page.php');
        }

        ?>

</form>

希望这有助于你

Answer 5

您的表单会向page.php发送帖子。因此，您需要将会话条件移至page.php。

另外，您可以将表格发送给自己并在之后重定向：

<?php session_start();?>

<form action="" method="post">

        Username: <input type="text" name="username" value="" /><br />
        Password: <input type="password" name="password" value="" /><br />
        <br />
        <input type="submit" name="submit" value="Submit" />

        <?php

        if (isset($_POST['submit'])) {
            $username = $_POST['username'];
            $password = $_POST['password'];
            $submit = $_POST['submit'];

            $_SESSION['username'] = $username;
            $_SESSION['password'] = $password;
            $_SESSION['submit'] = $submit;
            header('page.php');
        }

    $username = isset($_SESSION["username"]) ? $_SESSION["username"] : "";
    $password = isset($_SESSION["password"]) ? $_SESSION["password"] : "";

    $submit = isset($_SESSION["submit"]) ? $_SESSION["submit"] : "";


    if(($username == "username") && ($password == "password")) {
        echo "You are logged in";
    } else {
        echo "Denied access";
    }

        ?>

</form>

为什么这个会话形式不起作用？

5 个答案: