这是我收到的错误:
Fatal error: Call to a member function getAttribute() on a non-object
in /home/a4688869/public_html/random/index.php
on line 45
这是一张图片:http://prntscr.com/5rum9z
该功能适用于前几个,但在显示几张照片后中断。本质上,代码生成一个随机的html。我使用cURL获取html,然后用函数解析它,然后从站点中选择一个图像,然后重复该过程,直到我得到5个图像。
我的代码
$original_string = '123456789abh';
$random_string = get_random_string($original_string, 6);
//Generates a random string of characters and returns the string
function get_random_string($valid_chars, $length)
{
$random_string = ""; // start with an empty random string
$num_valid_chars = strlen($valid_chars); // count the number of chars in the valid chars string so we know how many choices we have
// repeat the steps until we've created a string of the right length
for ($i = 0; $i < $length; $i++)
{
$random_pick = mt_rand(1, $num_valid_chars); // pick a random number from 1 up to the number of valid chars
// take the random character out of the string of valid chars
// subtract 1 from $random_pick because strings are indexed starting at 0, and we started picking at 1
$random_char = $valid_chars[$random_pick-1];
$random_string .= $random_char; // add the randomly-chosen char onto the end of our string so far
}
return $random_string;
}
//Parses the random website and returns the image source
function websearch($url){
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$html = curl_exec($ch);
curl_close($ch);
$dom = new DOMDocument;
@$dom->loadHTML($html); // Had to supress errors
$img = $dom->getElementsByTagName('img')->item(1); //Get just the second picture
$src = $img->getAttribute('src'); //Get the source of the picture
return $src;
}
显示html的代码部分
for ($i = 0; $i < $perpage; $i++){
$random_string = get_random_string($original_string, 6);
$src = websearch('http://prntscr.com/' . $random_string);
while( $src == "http://i.imgur.com/8tdUI8N.png"){
$random_string = get_random_string($original_string, 6);
$src = websearch('http://prntscr.com/' . $random_string);
}
?>
<img src="<?php echo $src; ?>">
<p><a href="<?php echo $src; ?>"><?php echo $src; ?></a></p>
<?php if ($i != $perpage - 1){ // Only display the hr if there is another picture after it ?>
<hr>
<?php }}?>
答案 0 :(得分:4)
每当你得到&#34;非对象&#34;错误是因为你在一个不是对象的变量上调用方法。
这可以通过始终检查您的返回值来解决。它可能不是很优雅,但计算机是愚蠢的,如果你想让你的代码工作,那么你必须始终确保它能做你想做的事。
$img = $dom->getElementsByTagName('img')->item(1);
if ($img === null) {
die("The image was not found!");
}
你也应养成阅读你正在使用的东西的文档的习惯(在这种情况下是返回值)。
正如您在DOMNodelist::item
页面上看到的那样,如果方法失败,返回值为null
:
返回值
DOMNodeList中索引位置的节点,如果不是有效索引,则为NULL。