Question

class / dbConnect.php page

class dbConnect {
    /*
     * initiate mysql database host,username,password,database name
     */

    private $host;
    private $dbName;
    private $uname;
    private $upass;
    private $con;

    public function __construct($host, $database, $userName, $password) {
        $this->host = $host;
        $this->dbName = $database;
        $this->uname = $userName;
        $this->upass = $password;
        $this->connectDB();
    }

    public function connectDB() {
        /*
         * @var $dsn mean data source name for pdo connection
         */
        $dsn = "mysql:host=" . $this->host . ";dbName=" . $this->dbName;
        try {
            $this->con = new PDO($dsn, $this->uname, $this->upass);            
        } catch (Exception $e) {
            echo $e->getMessage();
        }
    }

}

class/sampleView.php

/*
 * include dbConnect class for this SampleView Class Page
 */
require_once './dbConnect.php';



class sampleViews extends dbConnect{

     function viewUsers(){
         /*
          * dbConncect Class Connection variable access
          */
         $connection = $this->con;

     }
}

这是正确的吗？我无法访问dbConnect Class $ con varibale使用$ this-＆gt;带有sampleView类的方法

并且可以通过这种方式完成不同的位置类扩展，包括页面。帮助Plezzzz

Answer 1

即使扩展父类，也无法访问private个变量。您需要将其更改为protected：

protected $con;

您还需要构造父类，否则它将不会实例化父（扩展）类。

function __construct() {
    parent::__construct($host, $username, $password, $db);
}

^{以上内容将在class SimpleViews extends dbConnect {....班级}

内

Answer 2

dbConnect页面

改变

protected $host;
protected $dbName;
protected $uname;
protected $upass;
protected $con;

和SampleView页面

public function __construct() {
    parent::__construct('localhostr', 'test', 'root', '');
}

function chkConnection() {
    /*
     * dbConncect Class Connection variable access
     */
    $dbcon = $this->con;
    if ($dbcon) {
        echo "successfully Connect database";
    } else {
        echo "sorry Could not be connect databsae";
    }
}

有人会更正我的代码吗？

带有PDO连接的OOP PHP包括不同的页面类

2 个答案: