Question

我正在尝试使用以下代码将字典的键从字符串转换为整数：

b = {"1":0,"2":0,"3":0,"4":0,"5":0}

for newkey in b:
        newkey[key] = int(newkey[key])
print b

然而，这会产生以下错误：

Traceback (most recent call last):
  File "C:\Python27\counter2", line 22, in <module>
    newkey[key] = int(newkey[key])
NameError: name 'key' is not defined

我希望最终输出看起来像这样：

b = {1:0,2:0,3:0,4:0,5:0}

谁能告诉我我做错了什么？

由于

Answer 1

在此代码中

for newkey in b:
        newkey[key] = int(newkey[key])

之前从未定义过

key。也许你的意思是newkey？相反，只需用字典理解重建字典，就像这样

>>> b = {"1": 0, "2": 0, "3": 0, "4": 0, "5": 0}
>>> {int(key):b[key] for key in b}
{1: 0, 2: 0, 3: 0, 4: 0, 5: 0}

或者你可以使用dict.iteritems()，就像这样

>>> {int(key): value for key, value in b.iteritems()}
{1: 0, 2: 0, 3: 0, 4: 0, 5: 0}

Answer 2

您从未定义过key

你可以做到

new_b = {int(old_key): val for old_key, val in b.items()}
# int(old_key) will be the key in the new list

Answer 3

由于您正在循环字典b，您可能想要

for newkey in b:
    b[newkey] = int(b[newkey])
print b

但这根本没有意义，它改变了“价值”，而不是“关键”。

您可能希望这样做：

b = {int(key):value for key, value in b.items()}

将字典键从字符串更改为整数

3 个答案: