我想计算限制在给定资助者和会计年度的每个问题的项目数量,金额和百分比。出于某种原因,当我运行下面的查询时,我没有看到null 来自左连接的值。
项目和问题之间的关系是一个问题可以有很多项目。问题表由目标表链接。
已更新
select
q.sp_question_id,
count(p.project_id) as projectCount,
sum(p.funding) as amount,
round(sum(p.funding)/sum(sum(p.funding)) over() *100) as percentTotal
from questions q
left join projects p on p.fiscal_year = q.fiscal_year
join objectives o on o.sp_objective_id = p.sp_objective_id
and o.sp_question_id = q.sp_question_id
and o.fiscal_year = p.fiscal_year
and o.fiscal_year = 2014
join funders f on p.funder_id = f.funder_id
where f.funder_short_name ='foo'
and q.fiscal_year = 2014
group by q.sp_question_id
order by q.sp_question_id;
questionId projectCount amount percentTotal
q1 14 54510 4
q2 29 1083598.72 76
q3 1 19900 1
q4 5 145631 10
q5 1 124999 9
q6 1 0 0
questionId projectCount amount percentTotal
q1 14 54510 4
q2 29 1083598.72 76
q3 1 19900 1
q4 5 145631 10
q5 1 124999 9
q6 1 0 0
q7 <null> <null> <null>
select
q.sp_question_id,
count(p.project_id) as projectCount,
sum(p.funding) as amount,
round(sum(p.funding)/sum(sum(p.funding)) over() *100) as percentTotal
from questions q
left join projects p on p.fiscal_year = q.fiscal_year
left join objectives o on o.sp_objective_id = p.sp_objective_id
and o.sp_question_id = q.sp_question_id
and o.fiscal_year = p.fiscal_year
and o.fiscal_year = 2014
left join funders f on p.funder_id = f.funder_id
where f.funder_short_name ='foo'
and q.fiscal_year = 2014
group by q.sp_question_id
order by q.sp_question_id;
questionId projectCount amount percentTotal
na 51 1428638.72 11
q1 51 1428638.72 11
q2 51 1428638.72 11
q3 51 1428638.72 11
q4 51 1428638.72 11
q5 51 1428638.72 11
q6 51 1428638.72 11
q7 51 1428638.72 11
qother 51 1428638.72 11
select
q.sp_question_id,
count(p.project_id) as projectCount,
sum(p.funding) as amount,
round(sum(p.funding)/sum(sum(p.funding)) over() *100) as percentTotal
from questions q
left join projects p on p.fiscal_year = q.fiscal_year
left join objectives o on o.sp_objective_id = p.sp_objective_id
and o.sp_question_id = q.sp_question_id
and o.fiscal_year = p.fiscal_year and o.fiscal_year = 2014
left join funders f on p.funder_id = f.funder_id and f.funder_short_name ='foo'
where q.fiscal_year = 2014
group by q.sp_question_id
order by q.sp_question_id;
questionId projectCount amount percentTotal
na 1225 299628985.01 11
q1 1225 299628985.01 11
q2 1225 299628985.01 11
q3 1225 299628985.01 11
q4 1225 299628985.01 11
q5 1225 299628985.01 11
q6 1225 299628985.01 11
q7 1225 299628985.01 11
qother 1225 299628985.01 11
答案 0 :(得分:6)
你遇到的问题与sql最未知的问题之一有关:关系的传递性。
您正在项目和问题之间进行可选(外部)联接,但您要求项目和目标(以及资助者)之间的强制(内部联接)关系:
计算中间结果集的及物性系统给出了内连接的普遍性,因此基本上意味着忽略了中间的外连接。确切地说,它不会被忽略,但它会变成内部连接。
你得到的是内部连接一直向下的结果,而你实际上期望左连接表现为原样,并返回与任何项目无关的问题的空行......但是如上所述,引擎不能像这样工作。
在我的脑海中,我只是认为你可以一直使用左连接。但是,您可能会遇到比预期更多的空行。这实际上取决于您对数据做了什么。
此外,您的查询中似乎有一个应该修改的广泛联接。请试试这个:
select
q.sp_question_id,
count(p.project_id) as projectCount,
sum(p.funding) as amount,
round(sum(p.funding)/sum(sum(p.funding)) over() *100) as percentTotal
from questions q
left join objectives o on
o.sp_question_id = q.sp_question_id
and o.fiscal_year = 2014
left join projects p on o.fiscal_year = p.fiscal_year and o.sp_objective_id = p.sp_objective_id
left join funders f on p.funder_id = f.funder_id and f.funder_short_name ='foo'
where q.fiscal_year = 2014
group by q.sp_question_id
order by q.sp_question_id;
答案 1 :(得分:0)
我最后通过左边连接两个子查询做了一些可怕的事情。如果有人有更好的方法,请发帖。
select t1.sp_question_id, t2.projectCount, t2.amount, t2.percentTotal
from (select
q.sp_question_id
from questions q
where q.fiscal_year = 2014) t1
left join
(select
q.sp_question_id,
count(p.project_id) as projectCount,
sum(p.funding) as amount,
round(sum(p.funding)/sum(sum(p.funding)) over() *100) as percentTotal
from questions q
left join projects p on p.fiscal_year = q.fiscal_year
join objectives o on o.sp_objective_id = p.sp_objective_id
and o.sp_question_id = q.sp_question_id
and o.fiscal_year = p.fiscal_year
join funders f on p.funder_id = f.funder_id
where f.funder_short_name ='foo'
and q.fiscal_year = 2014
group by q.sp_question_id
order by q.sp_question_id) t2
on t1.sp_question_id = t2.sp_question_id