Question

问题：我正在创建一个数组或多个数组来写入值，并继续这样做，直到绘制出某个值。此代码的长视图是使用这些值将一个字母与另一个字母匹配。（即第二次世界大战中使用的炸弹。）除此之外，它将是完全数字化的。 Bombe是一个解密者，发现一个字母能够映射到另一个字母。（Enigma示例将在评论中发布。）我正在尝试使用此解密任何消息。

理解：我不记得很多代码，特别是因为我之前从未使用过google-apps-script。我没有基本的想法，但是一些语法不同我迷失了。（即：而不是System.out.print();它将是Logger.log(data);。到目前为止，这就是我从中得到的所有内容。我已经找到了一些可以找到的代码here。

背景：这是我理解的相当多的文字，但在你标记我之前听我说，继续前进。在上面注释中发布的“Enigma example”字样下的超链接显示了我正在尝试反向执行的映射。然而，我需要创建我不记得如何创建的循环和变量。我有关于Enigma和Bombe的信息：Enigma & Bombe info。我已经在谷歌之类的网站上进行了一些搜索，但是没有任何我理解或有益于我的最终目标。我所得到的只是另一个链接，我将在评论中发布，它会向我显示一个基本的循环。

我需要帮助：我在以下方面寻求帮助：循环，变量和数组。建议对我来说是最有价值的，因为我在这里学习，而不是通过询问来完成我的工作。

想法：我有一些想法，垃圾收集器，多维数组和/或只是一系列可能性。（参见上面的“Enigma＆amp; Bombe信息”链接。

轻松复制/粘贴：

  function bombeCode1() {
   var fastRotor = ["A","B","C","D","E","F","G","H","I","J","K","L","M","N",
              "O","P","Q","R","S","T","U","V","W","X","Y","Z"];

  var mediumRotor = fastRotor;                 
  var slowRotor = fastRotor;

  var rows = 26;
  var columns = 26;

   for (var i=0; i < rows ; i++) {
    Logger.log('Outer Loop: value of i : ' + i);
   // Logger.log("Partition for Outer Loop");
   // Logger.log(" ");
    var fastRotorValue = fastRotor[i];

   for (var j=0; j < columns ; j++) {
     Logger.log('-Inner Loop value of j : ' +j);
     //var fastRotorValue = fastRotor[i];
     var medRotorValue = mediumRotor[j];

     // Logger.log("---- " + fastRotorValue + " " + medRotorValue);

      for (var k=0; k < 26 ; k++) {

     // Logger.log('---- XXXX Third Loop value of k : ' + k);
      //var fastRotorValue = fastRotor[i];
      //var medRotorValue = mediumRotor[j];
      var slowRotorValue = slowRotor[k];

       Logger.log("---- XXXX " + fastRotorValue + " " + medRotorValue + " " + slowRotorValue);
      };  //var objectNumberValuePair = {"0":"A", "1":"B",     "2":"C","3":"D","4":"E","5":"F","6":"G","7":"H","8":"I",
                          //       "9":"J","10":"K","11":"L","12":"M","13":"N","14":"O","15":"P","16":"Q","17":"R",
                          //        "18":"S","19":"T","20":"U","21":"V","22":"W","23":"X","24":"Y","25":"Z"}
                         //  Logger.log(slowRotorValue = objectNumberValuePair); 
                          //  Logger.log(medRoterValue = objectNumberValuePair);
                             //  Logger.log(fastRoterValue = objectNumberValuePair);
     }

   }
 }

Answer 1

这是我稍微修改过的代码，只是为了在Logger打印输出中显示循环值。

function bombeCode1() {
  var fastRotor = ["A","B","C","D","E","F","G","H","I","J","K","L","M","N",
                  "O","P","Q","R","S","T","U","V","W","X","Y","Z"];

  var mediumRotor = fastRotor;                 
  var slowRotor = fastRotor;

  var rows = 3;
  var columns = 6;                    

  for (var i=0; i < rows ; i++) {
    Logger.log('Outer Loop: value of i : ' + i);
    Logger.log("Partition for Outer Loop");
    Logger.log(" ");

    for (var j=0; j < columns ; j++) {

      Logger.log('----Inner Loop value of j : ' + j);

      var fastRoterValue = fastRotor[i];
      var medRoterValue = mediumRotor[j];

      Logger.log("---- " + fastRoterValue + " " + medRoterValue);

      for (var k=0; k < 6 ; k++) {

        Logger.log('---- XXXX Third Loop value of k : ' + k);
        var fastRoterValue = fastRotor[i];
        var medRoterValue = mediumRotor[j];
        var slowRotorValue = slowRotor[k];

        Logger.log("---- XXXX " + fastRoterValue + " " + medRoterValue + " " + slowRotorValue);
      };
    }

  }
}

运行它，看看你的想法。我确定这不是你需要的，而是从某个地方开始。

在google-apps-script中处理脚本，有什么建议吗？

1 个答案: