Question

我正在尝试将activiti modeler与我的Web应用程序集成。我的应用程序包括一些jar模块和三个war模块。战争模块之一我想与activiti建模者整合。我发现了这个提示How To Integrate Activiti Modeller Into own Web Application。我已经完成了这个主题，但这对我没用。我从ServerServlet收到404错误。

这是我的配置：的web.xml

<servlet>
    <servlet-name>RestletServlet</servlet-name>
    <servlet-class>org.restlet.ext.servlet.ServerServlet</servlet-class>
    <init-param>
        <!-- Application class name -->
        <param-name>org.restlet.application</param-name>
        <param-value>org.activiti.rest.explorer.application.ExplorerRestApplication</param-value>
    </init-param>
</servlet>

<servlet-mapping>
        <servlet-name>RestletServlet</servlet-name>
        <url-pattern>/mymodule/service/*</url-pattern>
    </servlet-mapping>

的pom.xml：

 <dependency>
        <groupId>org.activiti</groupId>
        <artifactId>activiti-modeler</artifactId>
        <scope>compile</scope>
    </dependency>

当然，我提取了消息来源。

这是日志：

20:27:48,191 ERROR [STDERR] sty 12, 2015 8:27:48 PM org.restlet.engine.log.LogFilter afterHandle
INFO: 2015-01-12    20:27:48    127.0.0.1   -   127.0.0.1   8080    GET /workflow/service/editor    id=10001    404 0   0   1   http://localhost:8080   Mozilla/5.0 (Windows NT 6.1; WOW64; rv:34.0) Gecko/20100101 Firefox/34.0

Answer 1

看起来您没有公开建模者REST端点。请尝试以下web.xml设置：

<servlet>
    <servlet-name>RestletServlet</servlet-name>
    <servlet-class>org.restlet.ext.servlet.ServerServlet</servlet-class>
    <init-param>
        <!-- Application class name -->
        <param-name>org.restlet.application</param-name>
        <param-value>org.activiti.rest.modeler.application.ModelerRestApplication</param-value>
    </init-param>
</servlet>

<!-- Catch all service requests -->
<servlet-mapping>
    <servlet-name>RestletServlet</servlet-name>
    <url-pattern>/service/*</url-pattern>
</servlet-mapping>

将Activiti Modeler与我自己的Web应用程序集成

1 个答案: