Question

我的PHP应用程序中有一个如下所示的数组：

Array
(
    [0] => Array
        (
            [name] => Name1
            [language] => 1
        )

    [1] => Array
        (
            [name] => Name2
            [language] => 1
        )

)

如何检查值为1的“语言”是否尽可能有效地出现两次？

Answer 1

$dupe = 0;
foreach($yourarray as $key => $val) {
    if(array_key_exists($seen, $val['language'])) {
        // a duplicate exists!
        $dupe = 1;
        // could do other stuff here too if you want,
        // like if you want to know the $key with the dupe

        // if all you care about is whether or not any dupes
        // exist, you could use a "break;" here to early-exit
        // for efficiency. To find all dupes, don't use break.
    }
    $seen[$val['language']] = 1;
}

// If $dupe still = 0 here, then no duplicates exist.

Answer 2

尝试过PHP函数array_unique？

（阅读下面的评论/用户贡献说明，尤其是 regeda at inbox dot ru ，他为多维数组制作了一个递归函数）

PHP - 检查该值是否在数组中没有出现两次

2 个答案: