我正在为大学编写一个银行应用程序,我偶然发现了一个问题。让我们以我的班级客户的方法为例。
void Customer::create_customer_data() {
cout << "Client' Address: ";
getline(cin, clientAddress);
cin.ignore();
cout << "Client's birth date: ";
getline(cin, clientBirthDate);
cin.ignore();
cout << "Client's telephone number: ";
getline(cin, clientTelephoneNumber);
cin.ignore();
cin.clear(); }
在main函数中,我有一个switch语句来处理用户选择。
int main() {
int choice, _globalClientNumber = 0;
Customer a(_globalClientNumber);
cout << "Welcome to bank manager 1.0!" << endl;
do {
cout << "Main Menu"<< endl;
cout << "Create a new customer (1)" << endl;
cout << "Create a new account (2)" << endl;
cout << "Cash money into account (3)" << endl;
cout << "Cash money out of account (4)" << endl;
cout << "Transfer money between two accounts (5)" << endl;
cout << "See current status of a customer and its accounts (6)" << endl;
cout << "End Application (0)" << endl;
cout << "Choice: ";
cin >> choice;
switch (choice) {
case 1:
a.create_customer_data();
break;
case 2:
a.create_new_account();
break;
case 3:
a.cash_in();
break;
case 4:
a.cash_out();
break;
case 5:
a.transfer_money();
break;
case 6:
a.print();
break;
default:
break;
}
cout << endl;
}
while (choice != 0);
return 0; }
我一直存在的问题是do_ while循环正在处理create_customer_data方法在屏幕上写入的值。因此,如果create_customer_data中的clientTelephoneNumber不以0结尾,则主菜单会由do-while循环显示两次。如果有人能告诉我我的错误在哪里,我将不胜感激。
编辑:简短地说:选择变量被覆盖,do-while循环再次执行,导致双重打印菜单。