Question

var records = JSON.parse(JsonString);

for(var x=0;x<records.result.length;x++)
{
  var record = records.result[x];
  ht_text+="<b><p>"+(x+1)+" "
    +record.EMPID+" "
    +record.LOCNAME+" "
    +record.DEPTNAME+"  "
    +record.CUSTNAME
    +"<br/><br/><div class='slide'>"
    +record.REPORT
    +"</div></p></b><br/>";
}

当JsonString包含实体数组但单个实体失败时，上面的代码工作正常。结果未标识为数组！这有什么不对吗？

http://pastebin.com/hgyWw5hd

Answer 1

结果不是数组。你在JSON中看到任何方括号吗？你不可以。它不包含任何数组。

{"result": {"ID":"30","EMPID":"1210308550","CUSTID":"1003","STATUS":"2","DATEREPORTED":"1273234502","REPORT":"this is one more report!","NAME":"Sandeep Savarla","CUSTNAME":"Collateral","LOCID":"4","LOCNAME":"Vijayawada","DEPTNAME":"SALES"}}

当上述功能有效时，你能告诉我你的“有效”json是什么样的吗？

Answer 2

在迭代之前确保它是一个数组

if ( 'undefined' == typeof records.result.length )
{
  records.result = [records.result];
}

Answer 3

您的代码循环遍历records.result，就像它是一个数组一样由于它不是数组，因此您的代码不起作用。

这个最简单的解决方案是强制它进入一个数组，如下所示：

var array = 'length' in records.result ? records.result : [ records.result ];

for(var x = 0; x < array.length; x++) {
    var record = array[x];
    ...

Answer 4

在您的代码中result是一个对象，而不是一个数组。将它的值包含在方括号中，使其成为一个数组：

{"result": [{"ID":"30","EMPID":"1210308550","CUSTID":"1003","STATUS":"2","DATEREPORTED":"1273234502","REPORT":"this is one more report!","NAME":"Sandeep Savarla","CUSTNAME":"Collateral","LOCID":"4","LOCNAME":"Vijayawada","DEPTNAME":"SALES"}]}

解析JSON字符串的问题

4 个答案: