Question

现在我的数组看起来像这样

Array([0] => array([region]=>1[district]=>2[sell]=>3)
      [1] => array([region]=>1[district]=>3[sell]=>6)
      [2] => array([region]=>1[district]=>4[sell]=>9)
     )

我有一个像这样的其他数组

Array([0] => array([buy]=>3)
      [1] => array([buy]=>4)
      [2] => array([buy]=>5)
     )

所以问题是我如何组合两个数组使它看起来像这样？或者有没有方法将第二个数组推入第一个数组？

Array([0] => array([region]=>1[district]=>2[sell]=>3[buy]=>3)
      [1] => array([region]=>1[district]=>3[sell]=>6[buy]=>4)
      [2] => array([region]=>1[district]=>3[sell]=>9[buy]=>5)
     )

Answer 1

不要忘记函数式编程。

$existing = [
    ['a' => 1, 'b' => 2, 'c' => 3],
    ['a' => 4, 'b' => 5, 'c' => 6],
    ['a' => 5, 'b' => 8, 'c' => 9],
];
$newItems = [
    ['d' => 3],
    ['d' => 4],
    ['d' => 5]
];
// let's run over those arrays and do array_merge over items
$result = array_map('array_merge', $existing, $newItems);
var_dump($result);

P.S。使用array_replace_recursive

存在更简单的方法

$result2 = array_replace_recursive($existing, $newItems);

Answer 2

试试这个

$existing = array(
    0 => array('region'=>1, 'district'=>2, 'sell'=>3),
    1 => array('region'=>4, 'district'=>5, 'sell'=>6),
    2 => array('region'=>5, 'district'=>8, 'sell'=>9),
);

$newItems = array(
    0 => array('buy'=>3),
    1 => array('buy'=>4),
    2 => array('buy'=>5)
);

foreach($newItems as $i => $data){
    $key = array_pop(array_keys($data));
    $value = array_pop(array_values($data));
    $existing[$i][$key] = $value;
}

echo '<pre>'; print_r($existing); echo '</pre>';

如何将阵列组合或推送到现有阵列？

2 个答案:

PhpFiddle Demo