Question

import java.util.*;
public class HangManP5 
{
public static void main(String[] args) 
{
int attempts = 10;
int wordLength;
boolean solved;
Scanner k = new Scanner(System.in);
System.out.println("Hey, what's your name?");
String name = k.nextLine();
System.out.println(name+ ", hey! This is a hangman game!\n");
RandomWord(word);
int len = word.length();
char[] temp = new char[len];
for(int i = 0; i < temp.length; i++)
{
    temp[i] = '*';
}
System.out.print("\n");
System.out.print("Word to date: ");
while (attempts <= 10 && attempts > 0)
{
    System.out.println("\nAttempts left: " + attempts);
    System.out.print("Enter letter: ");
    String test = k.next();
    if(test.length() != 1) 
    {
        System.out.println("Please enter 1 character");
        continue;
    }
    char testChar = test.charAt(0);
    int foundPos = -2;
    int foundCount = 0;
    while((foundPos = word.indexOf(testChar, foundPos + 1)) != -1)
    {
        temp[foundPos] = testChar;
        foundCount++;
        len--;
    }
    if(foundCount == 0)
    {
        System.out.println("Sorry, didn't find any matches for " + test);
    }
    else
    {
        System.out.println("Found " + foundCount + " matches for " + test);
    }

    for(int i = 0; i < temp.length; i++)
    {
        System.out.print(temp[i]);
    }
    System.out.println();

    if(len == 0)
    {
        break; //Solved!
    }
    attempts--;
 }

if(len == 0)
{
    System.out.println("\n---------------------------");
    System.out.println("Solved!");
}
else
{
    System.out.println("\n---------------------------");
    System.out.println("Sorry you didn't find the mystery word!");
    System.out.println("It was \"" + word + "\"");
}
}
public static String RandomWord(String word)
{
//List of words
Random r = new Random();
int a = 1 + r.nextInt(5);
if(a == 1)
{
    word=("Peace");
}
if(a == 2)
{
    word=("Nuts");
}
if(a == 3)
{
    word=("Cool");
}
if(a == 4)
{
    word=("Fizz");
}
if(a == 5)
{
    word=("Awesome");
}
 return (word);
 }
 }

好的，所以这是我的刽子手游戏的代码，我唯一要做的就是让我的程序随机化其中一个单词，它应该在方法中成功完成。但我遇到的唯一问题是获取字符串变量＆＃34; word＆＃34; 返回主类（有错误强调所有＆＃34 ;主要类中的单词＆＃34; 变量。）

如果我可以通过这种或其他方式获得帮助，从列表中生成一个随机单词，那就太棒了。

Answer 1

在java中，参数按值传递，而不是通过引用传递。因此，您无法更改参数的引用。

在您的情况下，您需要：

public static String getRandomWord() {
    switch(new Random().nextInt(5)) {
        case 0:
            return "Peace";
        case 1:
            return "Nuts";
        // ...
        default:
            throw new IllegalStateException("Something went wrong!");
    }
}

在main：

// ...
String word = getRandomWord();
int len = word.length(); 
// ...

Answer 2

您无法修改来电者的参考资料。

RandomWord(word);

需要像

word = RandomWord(word);

此外，按照惯例，Java方法以小写字母开头。并且，您可以返回word而不会将其作为参数传入，我建议您保存Random引用并使用类似

的数组

private static Random rand = new Random();
public static String randomWord() {
    String[] words = { "Peace", "Nuts", "Cool", "Fizz", "Awesome" };
    return words[rand.nextInt(words.length)];
}

然后将其称为

word = randomWord();

如何返回一个字符串？

2 个答案: