Question

每次我尝试从php脚本在我的mysql数据库中插入值时，查询都会失败。

以下是我的代码。

if ( empty($_POST)) {
echo '<script type="text/javascript">
    alert("Tricky, you must have left something empty. That is why you are now will be redirected to Main page. Try again ;)");
    window.location.href ="index.php"</script>';


}else {
$first_name = $_POST['first_name'];
$last_name = $_POST['last_name'];
$email_id = $_POST['email_id'];
$your_info = $_POST['your_info'];
$title = $_POST['title'];
$feed_area = $_POST['feed_area'];
$remote_addr = $_SERVER['REMOTE_ADDR'];
$type = $_POST['type'];   
 if(!empty($first_name) || !empty($last_name) || !empty($email_id) || !empty($your_info) || !empty($title) || !empty($feed_area) || !empty($type))
 {
    echo '<div id="header">
    <div id="middle_heading">Confirmed!!!</div></div>';
    $dbc = mysqli_connect('localhost', 'root', '', 'feed_update');
    $query = "INSERT INTO feed_info (id, first_name, last_name, email_id, your_info, title,type, feed_area, feed_date, remote_addr)" VALUES (0, '$first_name', '$last_name', '$email_id', '$your_info', '$title', '$type', '$feed_area', NOW(), '$remote_addr')";
   mysqli_query($dbc, $query)
   or die("<script type='text/javascript'>alert('query error alert');</script>");   
   mysqli_close($dbc);
   echo '<script type="text/javascript">window.location.href ="index.php"</script>';
   }else {
     echo '<script type="text/javascript">
     alert("Tricky, you must have left something empty. That is why you are now will be redirected to Main page. Try again ;)");
     window.location.href ="index.php"</script>';
      }
    }
    ?>

注意：

html不是php自我形式。
我也在我的数据库中安装了wordpress，它也有问题吗？

Answer 1

得到答案，我的数据需要转义。 Short和Sweet使用mysql_real_escape_string

代表。 $first_name = mysql_real_escape_string($_POST['first_name']); $last_name = mysql_real_escape_string($_POST['last_name']);并且我知道您必须在思考，我使用mysqli但是，当我尝试mysqli_real_espace_string()时，它会显示错误。

抱歉，打扰你的人。

每次在INSERT INTO中mysqli_query都会死掉

1 个答案: