我正在处理一个学生项目,并尝试将处理过程中的JSON数据(基于Twitter主题标签'#tune')发送到Arduino,但方法' myPort.write (状态);'不能与JSON一起使用,我已经在网上查看但不确定使用什么命令 - 我是否在正确的轨道上?这是代码:
处理:
import processing.serial.*; //Serial connection for Arduino
import java.lang.reflect.Method;
import com.temboo.core.*; // Temboo library
import com.temboo.Library.Twitter.Search.*; // Temboo Twitter search library
// Create a session using your Temboo account application details
TembooSession session = new TembooSession("MYUSERNAME", "MYTEMBOOAPPNAME", "MYTEMBOOCODE");
// Setup objects
Serial myPort; // Create object from Serial class
int portNo = 7; // Define portNo as int
int baudRate = 9600; // Define baudRate as int
void setup() {
// Run the Tweets Choreo function
runTweetsChoreo();
String portName = Serial.list()[portNo]; // Setup String for port ([7] is the port number for my machine)
myPort = new Serial(this, portName, baudRate); // Setting up serial port
}
void runTweetsChoreo() {
// Create the Choreo object using your Temboo session
Tweets tweetsChoreo = new Tweets(session);
// Set credential
tweetsChoreo.setCredential("ArduinoUkulele");
// Set inputs
// Run the Choreo and store the results
TweetsResultSet tweetsResults = tweetsChoreo.run();
// retrieve the results as JSON
JSONObject results = parseJSONObject(tweetsResults.getResponse());
// retrieve the statuses from the results
JSONArray statuses = results.getJSONArray("statuses");
// loop through the statuses
for (int i = 0; i < statuses.size(); i++){
JSONObject status = statuses.getJSONObject(i);
println(status.getString("text"));
println(" -- -- -- -- -- -- -- -- -- -- -- -- -- -- ");
myPort.write(status); // THIS IS THE CODE NOT WORKING WITH JSON
}
}
Arduino的:
char val; // Data received from the serial port
int ledPin = 13; // Set the pin to digital I/O 13
void setup(){
pinMode(ledPin, OUTPUT); // Set pin as OUTPUT
Serial.begin(9600); // Start serial communication at 9600 bps
}
void loop(){
if (Serial.available()) { // If data is available to read,
val = Serial.read(); // read it and store it in val
Serial.println(val);
delay(10); // Wait 10 milliseconds for next reading
}
}
我确定我只是在寻找某个命令 - 一旦我收到了数据,我只是想根据接收到的新标签打开LED。任何帮助将不胜感激!
干杯
亚瑟
答案 0 :(得分:0)
write()方法不能将 JSONObject 作为输入,只能 byte [] ,字符串。但是你已经拥有了所需的一切:只需使用 getString()方法,就像你在上面两行一样(使用适当的密钥字符串,你应该从你在JSON之上使用的API知道) :
myPort.write(status.getString("text"));