我正在编写一个简单的tableview应用程序,当点击该行时,会显示警报。
(void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath{
NSString *rowValue =self.greekLetters[indexPath.row];
// NSString *message=[[NSString alloc] initWithFormat:@"You selected%@!",rowValue];
if (indexPath.row==0) {
NSString *message=[[NSString alloc] initWithFormat:@"This is course aaaaa",rowValue];
}
if (indexPath.row==1) {
NSString *message=[[NSString alloc] initWithFormat:@"This is course aaaaa"];
}
UIAlertView *alert=[[UIAlertView alloc] initWithTitle:@"Course introduction" message:message delegate:nil cancelButtonTitle:@"Return to courses list" otherButtonTitles:nil, nil];
[alert show];
[tableView deselectRowAtIndexPath:indexPath animated:YES];
但是,Xcode不喜欢我的if语句,而以下语句可以使用。
NSString *message=[[NSString alloc] initWithFormat:@"You selected%@!",rowValue];
有人能给我一个如何在这里使用这个消息的例子吗?
答案 0 :(得分:1)
这是范围问题。您需要在if语句之前声明消息:
NSString *message;
if (indexPath.row==0) {
message=[[NSString alloc] initWithFormat:@"This is course aaaaa",rowValue];
}
else if (indexPath.row==1) {
message=[[NSString alloc] initWithFormat:@"This is course aaaaa"];
}
UIAlertView *alert=[[UIAlertView alloc] initWithTitle:@"Course introduction" message:message delegate:nil cancelButtonTitle:@"Return to courses list" otherButtonTitles:nil];
[alert show];
[tableView deselectRowAtIndexPath:indexPath animated:YES];
但是,如果课程编号由行号确定:
NSString *rowValue =self.greekLetters[indexPath.row];
NSString *message = [[NSString alloc] initWithFormat:@"This is course %@",rowValue];
UIAlertView *alert=[[UIAlertView alloc] initWithTitle:@"Course introduction" message:message delegate:nil cancelButtonTitle:@"Return to courses list" otherButtonTitles:nil];
[alert show];
[tableView deselectRowAtIndexPath:indexPath animated:YES];
答案 1 :(得分:0)
您已忘记在第一个if语句中加入%@
。
NSString *message= [[NSString alloc] initWithFormat:@"This is course aaaaa %@",rowValue];
顺便说一下,根本不需要[[NSString alloc] init]
,只需使用[NSString stringWithFormat:...]