如果2个变量具有相同的状态，则更改变量的状态

Question

我不确定我的头衔很好地解释了我的问题，

基本上我有两个变量： -

public int driverNumberOne;
public int driverNumberTwo;

首先用户将driverNumberOne设置为int值，然后将driverNumberTwo设置为另一个int值，但我想要它做什么，当用户输入例如driverNumberTwo的int值时，我希望该方法将driverNumberOne的值更改为一个不同的值，所以我得到2变量具有相同的int值。 到目前为止，这是我的基本方法标题和正文，花了很多年时间试图弄清楚要做什么:-(

/**
 * Allows the user to change the number for driver one.
 */
public void setDriverNumberTwo(int aDriverNumber)
{
   this.setDriverNumberTwo(aDriverNumber);

Answer 1

public int driverNumberOne; 
public int driverNumberTwo;
public void setDriverNumberTwo(int aDriverNumber) {
    this.setDriverNumberTwo(aDriverNumber);
    if (this.driverNumberOne == this.driverNumberTwo) {
        ... change the value of the second variable to whatever ...
    }
}

Answer 2

public void setDriverNumberTwo(int aDriverNumber )
{
    this.setDriverNumberTwo(aDriverNumber);
    if (this.driverNumberOne == this.driverNumberTwo) {
        // Set this.driverNumberOne to any Random Number 
    }
}

Answer 3

我认为你写的方法会导致无限循环..

public void setDriverNumberTwo(int aDriverNumber ) {
    this.setDriverNumberTwo(aDriverNumber);// <- delete this line if you don't want an infinite loop method
    ...
}

你可以做你想做的正确方法是：

public void setDriverNumberTwo() {
    if (driverNumberOne == driverNumberTwo)
        driverNumberOne++;
}