我已经看过两个与我相似的问题,但这些问题的答案对我不起作用。我有一个旧项目,其中包含在一组方括号内手动输入的国家/地区列表。
我可以在我的pickerView中轻松使用它,但我想知道是否有更有效的方法来做到这一点?
我将使用UIPickerView中的国家/地区列表。
答案 0 :(得分:28)
您可以使用NSLocale类ISOCountryCodes()
方法获取国家/地区列表,该方法会返回[AnyObject]
数组,并将其转换为[String]
。从那里,您可以使用NSLocale的displayNameForKey
方法获取国家/地区名称。它看起来像这样:
var countries: [String] = []
for code in NSLocale.ISOCountryCodes() as [String] {
let id = NSLocale.localeIdentifierFromComponents([NSLocaleCountryCode: code])
let name = NSLocale(localeIdentifier: "en_UK").displayNameForKey(NSLocaleIdentifier, value: id) ?? "Country not found for code: \(code)"
countries.append(name)
}
println(countries)
答案 1 :(得分:15)
SWIFT 3和4
var countries: [String] = []
for code in NSLocale.isoCountryCodes as [String] {
let id = NSLocale.localeIdentifier(fromComponents: [NSLocale.Key.countryCode.rawValue: code])
let name = NSLocale(localeIdentifier: "en_UK").displayName(forKey: NSLocale.Key.identifier, value: id) ?? "Country not found for code: \(code)"
countries.append(name)
}
print(countries)
答案 2 :(得分:7)
与Ian相同但更短
let countries = NSLocale.ISOCountryCodes().map { (code:String) -> String in
let id = NSLocale.localeIdentifierFromComponents([NSLocaleCountryCode: code])
return NSLocale(localeIdentifier: "en_US").displayNameForKey(NSLocaleIdentifier, value: id) ?? "Country not found for code: \(code)"
}
print(countries)
答案 3 :(得分:5)
快速,您可以轻松检索国家名称及其标志表情符号。
import UIKit
class ViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
var countriesData = [(name: String, flag: String)]()
for code in NSLocale.isoCountryCodes {
let flag = String.emojiFlag(for: code)
let id = NSLocale.localeIdentifier(fromComponents: [NSLocale.Key.countryCode.rawValue: code])
if let name = NSLocale(localeIdentifier: "en_UK").displayName(forKey: NSLocale.Key.identifier, value: id) {
countriesData.append((name: name, flag: flag!))
}else{
//"Country not found for code: \(code)"
}
}
print(countriesData)
}
}
extension String {
static func emojiFlag(for countryCode: String) -> String! {
func isLowercaseASCIIScalar(_ scalar: Unicode.Scalar) -> Bool {
return scalar.value >= 0x61 && scalar.value <= 0x7A
}
func regionalIndicatorSymbol(for scalar: Unicode.Scalar) -> Unicode.Scalar {
precondition(isLowercaseASCIIScalar(scalar))
// 0x1F1E6 marks the start of the Regional Indicator Symbol range and corresponds to 'A'
// 0x61 marks the start of the lowercase ASCII alphabet: 'a'
return Unicode.Scalar(scalar.value + (0x1F1E6 - 0x61))!
}
let lowercasedCode = countryCode.lowercased()
guard lowercasedCode.count == 2 else { return nil }
guard lowercasedCode.unicodeScalars.reduce(true, { accum, scalar in accum && isLowercaseASCIIScalar(scalar) }) else { return nil }
let indicatorSymbols = lowercasedCode.unicodeScalars.map({ regionalIndicatorSymbol(for: $0) })
return String(indicatorSymbols.map({ Character($0) }))
}
}
结果:
答案 4 :(得分:4)
这是@ vedo27在Swift 3中的回答
let countries = NSLocale.isoCountryCodes.map { (code:String) -> String in
let id = NSLocale.localeIdentifier(fromComponents: [NSLocale.Key.countryCode.rawValue: code])
return NSLocale(localeIdentifier: "en_US").displayName(forKey: NSLocale.Key.identifier, value: id) ?? "Country not found for code: \(code)"
}
答案 5 :(得分:2)
将本地显示的国家/地区名称本地化也是一种很好的做法。所以除了vedo27的回答,它将是:
let countriesArray = NSLocale.ISOCountryCodes().map { (code:String) -> String in
let id = NSLocale.localeIdentifierFromComponents([NSLocaleCountryCode: code])
let currentLocaleID = NSLocale.currentLocale().localeIdentifier
return NSLocale(localeIdentifier: currentLocaleID).displayNameForKey(NSLocaleIdentifier, value: id) ?? "Country not found for code: \(code)"
}
答案 6 :(得分:2)
Swift 3声明为var
:
var countries: [String] {
let myLanguageId = "en" // in which language I want to show the list
return NSLocale.isoCountryCodes.map {
return NSLocale(localeIdentifier: myLanguageId).localizedString(forCountryCode: $0) ?? $0
}
}
答案 7 :(得分:2)
SWIFT 4
这是在Swift 4中实现它的一种优雅方式
var countries: [String] = {
var arrayOfCountries: [String] = []
for code in NSLocale.isoCountryCodes as [String] {
let id = NSLocale.localeIdentifier(fromComponents: [NSLocale.Key.countryCode.rawValue: code])
let name = NSLocale(localeIdentifier: "en_UK").displayName(forKey: NSLocale.Key.identifier, value: id) ?? "Country not found for code: \(code)"
arrayOfCountries.append(name)
}
return arrayOfCountries
}()
答案 8 :(得分:1)
或者,您可以在swift 4中使用它并使用系统语言进行本地化。
import Foundation
struct Country {
let name: String
let code: String
}
final class CountryHelper {
class func allCountries() -> [Country] {
var countries = [Country]()
for code in Locale.isoRegionCodes as [String] {
if let name = Locale.autoupdatingCurrent.localizedString(forRegionCode: code) {
countries.append(Country(name: name, code: code))
}
}
return countries
}
}
答案 9 :(得分:1)
Swift 4.2
let languageList = Locale.isoLanguageCodes.compactMap { Locale.current.localizedString(forLanguageCode: $0) }
let countryList = Locale.isoRegionCodes.compactMap { Locale.current.localizedString(forRegionCode: $0) }
答案 10 :(得分:1)
更新为vedo27的答案,但在 迅速5:
let countries : [String] = NSLocale.isoCountryCodes.map { (code:String) -> String in
let id = NSLocale.localeIdentifier(fromComponents: [NSLocale.Key.countryCode.rawValue: code])
return NSLocale(localeIdentifier: "en_US").displayName(forKey: NSLocale.Key.identifier, value: id) ?? "Country not found for code: \(code)"
}
对于按字母顺序排列的国家/地区也要有一个排序的数组,请在获取国家/地区列表后按您的顺序在下方添加
let sortedcountries = countries.sorted { $0 < $1 }
答案 11 :(得分:0)
这是Swift 5.1的代码(至少对我来说是有效的,因为许多功能已重命名):
let array = NSLocale.isoCountryCodes.map
{
(code:String) -> String in
let id = NSLocale.localeIdentifier(fromComponents: [NSLocale.Key.countryCode.rawValue: code])
let currentLocaleID = NSLocale.current.identifier
return NSLocale(localeIdentifier: currentLocaleID).displayName(forKey: NSLocale.Key.identifier, value: id) ?? "Country not found for code: \(code)"
}
这是一个[String]