Question

点击链接后，我想在Codeigniter中发送一个帖子：

我的HTML代码：

<a href="<?php echo site_url('clientes/delete/'); ?>" id="<?php echo $id; ?>">Delete</a>

我想使用post方法，因为使用csrf保护更安全。

由于

Answer 1

来源：http://jsfiddle.net/iam_groot/aaeftkhv/

您需要在html标头中为csrf保护创建一个全局变量：

<script>
var csrf_token_name = "<?php echo $this->security->get_csrf_token_name(); ?>";
var csrf_hash = "<?php echo $this->security->get_csrf_hash(); ?>";
</script>

编辑html链接：

<a href="http://httpbin.org/post" id="5" class="delete" onclick="return false;">Delete row</a>

并添加此javascript代码：

<script>
create_form_post = function(action, fields, target) {
    if(target == undefined) {
        target = '_self';
    }

    fields[csrf_token_name] = csrf_hash;

    id_form = makeid();
    $( '<form method="POST" action="'+action+'" target="'+target+'" id="'+id_form+'" style="display:none !important;"></form>' ).appendTo( "body" );
    $.each(fields, function( k, v ) {
        $( '<input name="'+k+'" value="'+v+'" type="hidden" />' ).appendTo( "form#"+id_form );
    });
    return id_form;
}


function makeid()
{
    var text = "";
    var possible = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";

    for( var i=0; i < 9; i++ )
        text += possible.charAt(Math.floor(Math.random() * possible.length));

    return text;
}

$(document).ready(function() {
    $("a.delete").click(function() {    
        if(confirm("¿Are you sure?")) {
            action = $(this).attr('href');
            delete_id = $(this).attr('id');
            id_delete_form = create_form_post(action, {id: delete_id});
            $("form#" + id_delete_form).submit();
        }
    });
});
</script>

Answer 2

使用AJAX

url = '<?php echo site_url('clientes/delete/'); ?>';
$('.delete').click(function(){
    clientId = $(this).attr('id');
    $.ajax({
      type: "POST",
      url: url, 
      data: { clientId: clientId }
    });
})

在控制器中

if(isset($_POST['clientId'] {
    $clientId = $_POST['clientId'];
} else {
    $clientId = 'No data';
}

如何通过CodeIgniter中的javascript发送帖子？

2 个答案: