我刚刚开始使用表达式树,所以我希望这是有道理的。我正在尝试创建一个表达式树来表示:
t => t.SomeProperty.Contains("stringValue");
到目前为止,我有:
private static Expression.Lambda<Func<string, bool>> GetContainsExpression<T>(string propertyName, string propertyValue)
{
var parameterExp = Expression.Parameter(typeof(T), "type");
var propertyExp = Expression.Property(parameter, propertyName);
var containsMethodExp = Expression.*SomeMemberReferenceFunction*("Contains", propertyExp) //this is where I got lost, obviously :)
...
return Expression.Lambda<Func<string, bool>>(containsMethodExp, parameterExp); //then something like this
}
我只是不知道如何引用String.Contains()方法。
帮助表示感谢。
答案 0 :(得分:125)
类似的东西:
class Foo
{
public string Bar { get; set; }
}
static void Main()
{
var lambda = GetExpression<Foo>("Bar", "abc");
Foo foo = new Foo { Bar = "aabca" };
bool test = lambda.Compile()(foo);
}
static Expression<Func<T, bool>> GetExpression<T>(string propertyName, string propertyValue)
{
var parameterExp = Expression.Parameter(typeof(T), "type");
var propertyExp = Expression.Property(parameterExp, propertyName);
MethodInfo method = typeof(string).GetMethod("Contains", new[] { typeof(string) });
var someValue = Expression.Constant(propertyValue, typeof(string));
var containsMethodExp = Expression.Call(propertyExp, method, someValue);
return Expression.Lambda<Func<T, bool>>(containsMethodExp, parameterExp);
}
您可能会发现this有帮助。
答案 1 :(得分:7)
这个怎么样:
Expression<Func<string, string, bool>> expFunc = (name, value) => name.Contains(value);
在客户端代码中:
bool result = expFunc.Compile()("FooBar", "Foo"); //result true
result = expFunc.Compile()("FooBar", "Boo"); //result false
答案 2 :(得分:0)
以下是如何创建string.Contains的表达式树。
var method = typeof(Enumerable)
.GetRuntimeMethods()
.Single(m => m.Name == nameof(Enumerable.Contains) && m.GetParameters().Length == 2);
var containsMethod = method.MakeGenericMethod(typeof(string));
var doesContain = Expression
.Call(containsMethod, Expression.Constant(criteria.ToArray()),
Expression.Property(p, "MyParam"));
的实际使用情况