Question

我正在使用rails routing，我想要像

这样的东西

resources :user
  member do
    resources :comments, shallow: true
  end
end

# To get the following routes
get /users/:id/comments (index)
post /users/:id/comments (create)
get /comments/:id (show)
put /comments/:id (update)
delete /comments/:id (destroy)

然而，shallowing不起作用，我有以下路线（更不用说用户的:id和评论是冲突的）

get /users/:id/comments
post /users/:id/comments
get /users/:id/comments/:id
put /users/:id/comments/:id
delete /users/:id/comments/:id

我知道通常推荐的做法是

resources :user
  resources :comments, shallow: true
end

# To get the following routes
get /users/:user_id/comments
post /users/:user_id/comments
get /comments/:id
put /comments/:id
delete /comments/:id

但是我希望在浅绿色路径create / index上的:id而不是params中使用:user_id。 This is usually done by using member

您可以省略：on选项，这将创建相同的成员路由，但资源ID值可用 params [：photo_id]而不是params [：id]。

是否有人知道为什么在member指令内完成后，shallowing无法正常工作？

Answer 1

member指令用于将成员路由添加到现有资源，而不是嵌套资源。我个人认为让:id引用索引中的父资源并创建操作是不明确/混乱但如果你真的在控制器中使用user_id而烦恼，你可以设置你的路由以下方式

resources :user do
  resources :comments, shallow: true, except: [:index, :create, :new, :edit]
end

get '/users/:id/comments', to: 'comments#index'
post '/users/:id/comments', to: 'comments#create'

这将为您提供以下路线

GET /users/:id/comments
POST /users/:id/comments
GET /comments/:id
PUT /comments/:id
DELETE /comments/:id

添加浅层资源作为另一个资源的成员

1 个答案: