Java @PathParam始终为null

时间:2015-01-09 14:33:33

标签: java rest jersey path-parameter

我正在尝试使用Jersey使用@PathParam,但它总是将其视为null。

这是方法: 网址为http://localhost:8080/GiftRegistryAPI/api/v2/inventory/david/v2/inventory为班级

package com.omar.rest.inventory;

import javax.websocket.server.PathParam;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.QueryParam;
import javax.ws.rs.core.Context;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.core.Request;
import javax.ws.rs.core.Response;

import org.codehaus.jettison.json.JSONArray;

import com.omar.rest.util.*;

@Path("/v2/inventory")
public class V2_Inventory {

@GET
@Produces(MediaType.APPLICATION_JSON)
public Response returnHostRegistries(@QueryParam("hostId") int hostId) throws Exception {

    String returnString = null;
    JSONArray jsonArray = new JSONArray();

    try {
        // A host ID of 0 indicates a null parameter, there will never be a host with an ID of 0
        if (hostId == 0) { 
            return Response.status(400).entity("Error: please provide a valid host ID for this search").build();
        }

        Schema dao = new Schema();
        jsonArray = dao.qryReturnHostRegistries(hostId);

        returnString = jsonArray.toString();
    }
    catch (Exception e) {
        e.printStackTrace();
        return Response.status(500).entity("Server was not able to process your request").build();
    }
    System.out.println(returnString);

    return Response.ok(returnString).build();

}

@Path("/{firstName}")
@GET
@Produces(MediaType.APPLICATION_JSON)
public Response returnSearchedRegistries(@PathParam("firstName") String name) throws Exception{

    String returnString = null;
    JSONArray jsonArray = new JSONArray();

    System.out.println("Name: " +name);
    try {
        Schema dao = new Schema();
        jsonArray = dao.qryReturnHostRegistries(name);

        returnString = jsonArray.toString();
    }
    catch (Exception e) {
        e.printStackTrace();
        return Response.status(500).entity("Server was not able to process your request").build();
    }

    System.out.println(returnString);

    return Response.ok(returnString).build();
}

}

调试后的name参数始终为空,我无法找到任何方法让它识别我输入了任何内容。

任何想法可能出错?

2 个答案:

答案 0 :(得分:9)

这是我的导入声明

import javax.websocket.server.PathParam;

应该是

import javax.ws.rs.PathParam;

答案 1 :(得分:0)

在此错误中,大多数情况下问题是错误的导入。只要确保您拥有import javax.ws.rs.PathParam;