Question

我有一个spimple脚本来重命名目录中的所有文件（例如475435_name.psd），方法是增加它的数字，比如10。

但是我收到了错误

Traceback (most recent call last):
  File "C:/Users/mstopienski/Desktop/Desktop/test.py", line 12, in <module>
    os.rename(filename, newname)
FileNotFoundError: [WinError 2] The system cannot find the file specified: '810858_Hero_ProjectHP_1600x487.psd' -> '810868_Hero_ProjectHP_1600x487.psd'

我不希望它移动文件我只想更改名称。

import glob, os
path = input()
for filename in glob.glob(path):
    number = filename[0:6]
    name = filename[6:]
    x = int(number)+10
    newname = (str(x) + name)
    os.rename(filename, newname)

Answer 1

根据@RvrK的评论，该脚本正在尝试定位重命名的工作目录，因此我猜测将最后一行转为：

os.rename(os.path.join(path, filename), os.path.join(path, newname))

应该这样做吗？

编辑：

添加一些'安全'功能：

import glob, os
path = input()
for filename in glob.glob(path):
    basename = os.path.basename(filename)
    number = basename [0:6]
    name = basename [6:]
    x = int(number)+10
    newname = (str(x) + name)
    os.rename(os.path.join(path, filename), os.path.join(path, newname))

Answer 2

您需要查看输入的路径并查看文件是否以＆＃39; .psd＆＃39;结尾，试试这段代码会有所帮助：

import os
path = raw_input()
for filename in os.walk(path):
  for ele in filename:
    if type(ele) == type([]) and len(ele)!=0:
      for every_file in ele:
        if every_file.endswith('psd'):

           number = every_file[0:6]
           name = every_file[6:]
           x = int(number)+10
           newname = (str(x) + name)
           os.rename(os.path.join(path, every_file), os.path.join(path, newname))

我把脚本和你的psd文件放在同一路径输入＆＃34; ./"它有效。

Python：重命名文件错误

2 个答案: