Question

我的代码：

FILE * file;

file = fopen("c://catalog//file.txt", "r");
int m,n; //size of 2d array (m x n)
fscanf(file, "%d", &m);
fscanf(file, "%d", &n);
fclose(file);

printf("Size: %d x %d\n", m, n);

// create 2d array 
char **TAB2 = new char*[m];
for (int i = 0; i < m; i++)
    char *TAB2 = new char[n];

// display 2d array 
for (int i = 0; i < m; i++){
    for (int j = 0; j < n; j++)
    {
        printf("%c ", &TAB2[i][j]);
    }
    printf("\n");
}

如何使用字符或字符串填充此数组？例如text =＆＃34; someting＆＃34;，对于数组3x5将是：

S o m e t
h i n g ?
? ? ? ? ?

我试过：TAB2 [0] [0] =＆＃39; s＆＃39; *＆amp; TAB2 [0] [0] =＆＃39; s＆＃39;对于一个char，这确实有效...

可能我使用指针（？）。有人帮我吗？

Answer 1

动态分配数组错误。

char **TAB2 = new char*[m];
for (int i = 0; i < m; ++i)
    TAB2[i] = new char[n];

请检查此link以获取帮助。

你可以试试这个：

#include<iostream>
using namespace std;

int main() {

  const int m = 3, n = 5;
  char **TAB2 = new char*[m];
  for (int i = 0; i < m; ++i)
      TAB2[i] = new char[n];

  char c;
  for (int i = 0; i < m; ++i) {
    for (int j = 0; j < n; ++j) {
      std::cin >> c;
      TAB2[i][j] = c;
    }
  }

  for (int i = 0; i < m; ++i) {
    for (int j = 0; j < n; ++j) {
      std::cout << TAB2[i][j];
    }
    std::cout << "\n";
  }

  // NEVER FORGET TO FREE YOUR DYNAMIC MEMORY
  for(int i = 0; i < m; ++i)
    delete [] TAB2[i];
  delete [] TAB2;

  return 0;
}

输出：

jorje
georg
klouv
jorje
georg
klouv

重要链接：

Answer 2

数组的分配似乎不正确;它应该如下。

char **TAB2 = new char*[m];
for (int i = 0; i < m; i++)
    TAB2[i] = new char[n];

如何将字符添加到2D数组？

2 个答案: