在我的控制器中我有方法
在带有表格的部分
中<form class="form-inline" role="form" ng-submit="deadForm()">
<div class="form-group">
<button ng-click="openJukeboxesModalToGroup()" class="btn btn-info">Add Stores to Group</button>
</div>
<div class="form-group">
<input type="text" ng-model="jukeboxFilter" ng-keypress="keyPressed($event, 'search')" class="form-control" placeholder="search">
</div>
<button type="button" ng-click="searchJukeboxes()" class="btn btn-info"><span class="glyphicon glyphicon-search"></span></button>
<button type="button" ng-click="resetFilter()" class="btn btn-info"><span class="glyphicon glyphicon-repeat"></span></button>
</form>
keyPressed方法是
$scope.keyPressed = function($event, eventType) {
$event.stopImmediatePropagation();
if(eventType=='search') {
if($event.which==13) {
$scope.searchJukeboxes();
}
}
};
无论何时有人在文本栏中输入内容并点击输入,我都会尝试启动搜索。但我不会以某种方式调用openJukeboxesModalToGroup()方法。我试图通过调用stop event proprpagation,更改openJukeboxesModalToGroup()方法的名称来阻止这种情况。但没有任何工作。对此有任何帮助。
deadForm()方法是实现,我在chrome console中没有收到任何错误。
答案 0 :(得分:4)
将openJukeBoxesModalToGroup()
的按钮更改为:
<button type="button" ng-click="openJukeboxesModalToGroup()" class="btn btn-info">Add Stores to Group</button>
问题是你没有提供一个类型,所以它将按钮分类为提交,在这种情况下,openJukeboxesModalToGroup()从你的输入submit
事件中被触发。
当你在表单中输入时会触发提交,我建议你通过ng-submit指令将你的方法添加到表单中,并使你的按钮成为提交...
<form class="form-inline" role="form" ng-submit="searchJukeboxes()">
<div class="form-group">
<button type="button" ng-click="openJukeboxesModalToGroup()" class="btn btn-info">Add Stores to Group</button>
</div>
<div class="form-group">
<input type="text" ng-model="jukeboxFilter" ng-keypress="keyPressed($event, 'search')" class="form-control" placeholder="search">
</div>
<button type="submit" ng-click="searchJukeboxes()" class="btn btn-info"><span class="glyphicon glyphicon-search"></span></button>
<button type="button" ng-click="resetFilter()" class="btn btn-info"><span class="glyphicon glyphicon-repeat"></span></button>
</form>