Question

我从C ++函数调用Python函数，如下所示。

void CPPFunction(PyObject* pValue)
{
  ...
  pValue = PyObject_CallObject(PythonFunction, NULL);
  ...
}

int main()
{
  PyObject *pValue = NULL;
  CPPFunction(PValue);
  int result_of_python_function = Pylong_aslong(PValue);
}

我想在CPPFunction之外访问python函数的返回值。由于PyObject_CallObject返回的PObject *的范围在CPPFunction内，如何访问CPPFunction外的值？

Answer 1

像在其他地方一样从函数返回它。

PyObject* CPPFunction()
{
    // ...
    PyObject* pValue = PyObject_CallObject(PythonFunction, NULL);
    // ...
    return pValue;
}

int main()
{
  PyObject *value = CPPFunction();
  int result_of_python_function = Pylong_aslong(value);
}

Answer 2

进行以下更改，你可以访问CPPFunction以外的python函数的返回值。希望这有助于：

PyObject* CPPFunction(PyObject* PythonFunction) // changes return type from void to PyObject and pass PythonFunction to be called
{
  pValue = PyObject_CallObject(PythonFunction, NULL);
  return pValue;
}

int main()
{
   PyObject *pValue = NULL;
   pValue = CPPFunction(PythonFunction); // assign return value from CPPFunction call to PyObject pointer pvalue
   long int result_of_python_function = Pylong_aslong(PValue);// data type changed from int to long int
   cout << result_of_python_function << endl; // just printing the python result
}

如何复制PyObject *？

2 个答案: