我想在每个条形图的外部顶部显示每个条形峰值的条形图。但据我所知,是代表酒吧内的每个酒吧价值。但那不是我想要的。正如您在附图中看到的那样,x轴的底部是混乱的。我认为我们必须将svg代码移出数据循环并使用svg.data(someData).enter()
来解决此问题,但我尝试了这样做但不成功。请建议我如何修改以下代码。
<!DOCTYPE html>
<meta charset="utf-8">
<style>
.axis {
font: 12px sans-serif;
}
.axis path,
.axis line {
fill: none;
stroke: #000;
shape-rendering: crispEdges;
}
.chart text {
fill: black;
font: 15px sans-serif;
text-anchor: middle;
}
</style>
<svg class="chart"></svg>
<script src="http://d3js.org/d3.v3.min.js"></script>
<script>
var margin = {top: 30, right: 80, bottom: 40, left: 100},
width = 960 - margin.left - margin.right,
height = 500 - margin.top - margin.bottom;
var color = d3.scale.category10();
var x = d3.scale.ordinal()
.rangeRoundBands([0, width], .2);
var y = d3.scale.linear()
.range([height, 0]);
var xAxis = d3.svg.axis()
.scale(x)
.orient("bottom");
var yAxis = d3.svg.axis()
.scale(y)
.orient("left");
function unit (d) {
count = 0, download = 0;
num = d.value;
while((num) >= 1)
{
num/=10;
++count;
}
switch (count) {
case 4 : download = ((d.value/1000).toFixed(2)) + " MB" ;
break;
case 8 : download = ((d.value/1000 * 1000).toFixed(2)) + " GB" ;
break;
default: download = ((d.value/1000).toFixed(2)) + " MB" ;
}
return download;
}
var chart = d3.select("body").append("svg")
// line = d3.select("body").append("svg")
.attr("width", width + margin.left + margin.right)
.attr("height", height + margin.top + margin.bottom)
.append("g")
.attr("transform", "translate(" + margin.left + "," + margin.top + ")");
var bar;
d3.csv("data.csv", type, function(error, data) {
x.domain(data.map(function(d) { return d.name; }));
y.domain([0, d3.max(data, function(d) { return d.value; })]);
chart.append("g")
.attr("class", "x axis")
.attr("transform", "translate(0," + height + ")")
.call(xAxis)
.append("text")
.attr("x", 790 )
.attr("y", 15 )
.style("text-anchor", "bottom")
.text("Clients");
chart.append("g")
.attr("class", "y axis")
.call(yAxis)
.append("text")
//.attr("transform", "rotate(-90)")
.attr("y", 1)
.attr("dy", ".71em")
.style("text-anchor", "end")
.text("Kilo Bytes");
bar = chart.selectAll("g")
.data(data)
.enter().append("g")
.attr("transform", function(d) { return "translate(" + x(d.name) + ",0)"; });
bar.append("rect")
.style("fill", function(d) { return color(d.name); })
.attr("y", function(d) { return y(d.value);})
.attr("height", function(d) { return height - y(d.value); })
.attr("width", x.rangeBand());
bar.append("text")
.attr("x", x.rangeBand() / 2 )
.attr("y", function(d) { return y(d.value) + 2 ; })
.attr("dy", "1em")
.attr("text-anchor", "middle")
.attr("font-size", "14px")
.attr("fill", "black")
.text(function(d) { return unit(d); });
});
function type(d) {
d.value = +d.value; // coerce to number
return d;
}
</script>
,数据采用csv格式,如下所示:
name,timesatmp,value
98.226.148.140,1341677167454,1
98.226.148.140,1341677167461,3
98.226.148.141,1341677167916,4
98.226.148.141,1341677167935,6
98.226.148.142,1341677167944,7
98.226.148.142,1341677167945,32
请建议我如何正确显示显示器。
答案 0 :(得分:1)
首先修改一下条形图,否则不会显示任何条形图:
<强> HTML:强>
<svg class="chart"></svg>
到
<body class="chart"></body>
<强> JS:强>
bar = chart.selectAll(".bar")
.data(data)
.enter().append("g")
.attr('class', 'bar')
.attr("transform", function(d) { return "translate(" + x(d.name) + ",0)"; });
并且要调整峰值,只需按以下方式添加翻译:
bar.append("text")
.attr("x", x.rangeBand() / 2 )
.attr("y", function(d) { return y(d.value) + 2 ; })
.attr("dy", "1em")
.attr("text-anchor", "middle")
.attr("font-size", "14px")
.attr("fill", "black")
.attr("transform", function(d) { return "translate(0, -20)"; })
.text(function(d) { return unit(d); });
答案 1 :(得分:1)
RPLACE:
d3.csv("data.csv", type, function(error, data) {
x.domain(data.map(function(d) { return d.name; }));
y.domain([0, d3.max(data, function(d) { return d.value; })]);
使用:
d3.csv("data.csv", type, function(error, data) {
x.domain(data.map(function(d) { return d.name; }));
y.domain([0, d3.max(data, function(d) { return d.value; })]);
var nestedData = d3.nest()
.key(function(d) { return d.name; }).entries(data);
var newData = [];
nestedData.forEach(function(d){
newData.push({name:d.key, value: d3.max(d.values, function(d) {return d.value})});
});