Question

我有一个隐藏的选择下拉列表，根据用户选择动态显示。提交表单后，所有表单字段（包括隐藏表单）都将发布到PHP脚本。表单使用ajax提交。有没有办法禁用隐藏字段提交。谢谢。

Ajax：

$("#new-contact-form").validate({
            rules: {
                contact_fname: "required",
                contact_lname: "required",
            },
            messages: {
                contact_fname: "First name is missing",
                contact_lname: "Last name is missing",
            },
            submitHandler: function(form) {
              $.ajax ({
                type:"POST",
                url:"../includes/functions/contact-functions.php",
                data: $('form#new-contact-form').serialize(),
                success: function(msg){
                  closeModal();
                  //notify();
                  location.reload();

                },
              });
            }
        });

模态/形式仅部分（非常长形式）：

 <div class="form-group ">
      <label  class="col-lg-3 col-sm-2 control-label">Contact Type</label>
     <div class="col-lg-4">
        <select class="form-control m-bot15" id="contact_type">
            <option value="None"> Contact Type</option>
            <option value="Account">Account</option>
            <option Value="Service_provider">Service Provider</option>
            <option value="Lead">Lead</option>
        </select>
      </div>
      <!--Start Contact Type inputs-->                                                
          <!-- Show Accounts -->
     <div class="col-lg-5 ">
        <select class="form-control m-bot15 " id="accounts_list" name="contact_account_name" style="display:none">
            <option value="no-account">Select Account</option>
            <?php list_accounts();?>
            <option value="Other_Account">Other</option>
        </select>
      </div>                                                
      <!--Show Service Providers-->
     <div class="col-lg-5 ">
            <select class="form-control m-bot15 " id="providers_list" name="contact_sp_name" style="display:none">
            <option value="no-sp">Select Service Provider</option>
                <?php list_providers();?>
                <option value="Other_Provider">Other</option>
            </select>
          </div>      
    </div>

功能：

if ($_POST['contact_account_name']!='Other_Account' && $_POST['contact_account_name'] != 'no-account' && $_POST['contact_sp_name'] = 'no-sp') {

        $current_account_id = $_POST['contact_account_name'];
        $result = "INSERT INTO contacts (contact_fname, contact_lname, contact_email, contact_phone, contact_fax, contact_account_id, contact_type)
        VALUES ('$contact_fname', '$contact_lname', '$contact_email', '$contact_phone', '$contact_fax', '$current_account_id', 1)";

        mysqli_query($connection, $result);
        if (!$result) {
            printf("Error: %s\n", mysqli_error($connection));
         exit();
                }
                echo "new ct insert";
        }

        //insert contact with new account
        elseif ($_POST['contact_account_name'] ='Other_Account' && $_POST['contact_sp_name'] = 'no-sp' ){
                $new_account_name = $_POST['new_account_name'];
                $new_account = "INSERT INTO accounts (account_name, account_address1, account_address2, account_city, account_state, account_zip, account_phone)
        VALUES ('$new_account_name', '$contact_address1', '$contact_address2', '$contact_city', '$contact_state', '$contact_zip', '$contact_phone')";

        mysqli_query($connection, $new_account);
        if (!$new_account) {
            printf("Error: %s\n", mysqli_error($connection));
         exit();
                }
                echo "new acct insert";

                $new_account_inserted_id = mysqli_insert_id($connection);

                $result = "INSERT INTO contacts (contact_fname, contact_lname, contact_email, contact_phone, contact_fax, contact_account_id, contact_type)
                VALUES ('$contact_fname', '$contact_lname', '$contact_email', '$contact_phone', '$contact_fax', '$new_account_inserted_id', 1)";

                mysqli_query($connection, $result);
                if (!$result) {
                    printf("Error: %s\n", mysqli_error($connection));
                 exit();
                        }
                                        echo "new ct with act insert";

        }

        //insert contact with existing SP
        elseif ($_POST['contact_sp_name']!='Other_Account'  && $_POST['contact_account_name'] = 'no-account') {

        $current_sp_id = $_POST['contact_sp_name'];
        $result = "INSERT INTO contacts (contact_fname, contact_lname, contact_email, contact_phone, contact_fax, contact_account_id, contact_type)
        VALUES ('$contact_fname', '$contact_lname', '$contact_email', '$contact_phone', '$contact_fax', '$current_sp_id', 2)";

        mysqli_query($connection, $result);
        if (!$result) {
            printf("Error: %s\n", mysqli_error($connection));
         exit();
                }
                                echo "new sp insert";

        }

Answer 1

我可以看到这样的事情：

$('#myForm').submit(function() {

    var $fields = $('#myForm :input');

    $fields.each(function() {

        if( $(this).val() == "") {

             $(this).remove(); 
        }
    });

    // submit remaining forms data
});

禁用隐藏字段的提交

1 个答案: