Question

这是我的代码，通过从用户那里获取5个输入来显示最小和最大整数...它适用于最小值但不适用于最大值而我无法找出问题...请帮助

import java.util.Scanner;

public class LargestAndSmallestIntegers {

    public static void main(String[] args) {


        Scanner input=new Scanner(System.in);
        int a,b,c,d,e;
        int small,large;

        System.out.println("Enter five integer values...");



        a=input.nextInt();

        small=a;
        large=a;

        b=input.nextInt();

        if (small<b)
        {
            large=b;
        }

        else 
        {
            small=b;
        }
        c=input.nextInt();

        if  (small<c)
        {
            large=c;
        }

        else
        {
            small=c;
        }

        d=input.nextInt();
        if (small<d)
        {
            large=d;
        }

        else
        {
            small=d;
        }
        e=input.nextInt();
        if (small<e)
        {
            large=e;
        }

        else
        {
            small=e;
        }


        input.close();  
         System.out.printf("%d is smallest and %d is largest", small,large);        

    }   
}

Answer 1

private int a = input.nextInt(),
    b = input.nextInt(),
    c = input.nextInt(),
    d = input.nextInt(),
    e = input.nextInt();

private int small, large;

small = min(a,b);
small = min(small,c);
small = min(small,d);
small = min(small,e);

large = max(a,b);
large = max(large,c);
large = max(large,d);
large = max(large,e);

private int min(int a, int b) {
    if (a < b) return a else return b;
}

private int max(int a, int b) {
    if (a > b) return a else return b;
}

我认为这有效;）

Answer 2

它适用于最小值但不适用于最大值

正如lared指出的那样，与small进行比较以确定large是有缺陷的。您必须在比较逻辑中包含类似的内容：

    if (large < b)
    {
        large = b;
    }

除了您现有的比较：

    if (small > b)
    {
        small = b;
    }

Answer 3

你总是只检查最小值。你还需要检查

if (small<e)
        {
            if(large < e)
              {
                  large=e;
               }
        }

使用if / else的最小和最大整数

3 个答案: